Use the dichotomous key to identify these plant leaves.

Consider the following equivalent expressions: 38÷1312 and 38?ab What are the values of a and b? Enter the value of a followed b

Anna007 [38]

Answer:

a = 12

b = 13

Explanation:

Consider the following equivalent expressions: 38÷1312 and 38?ab What are the values of a and b? Enter the value of a followed by the value of b, separated by a comma.

The solution is attached.

3 0

3 years ago

Even at high T, the formation of NO is not favored:

Readme [11.4K]

Answer:

3,16x10⁻³M

Explanation:

For the reaction:

N₂(g) + O₂(g) ⇄ 2NO(g). The kc is defined as:

kc = [NO]² / [N₂] [O₂] = 4,10x10⁻⁴ (1)

If you add in a 1,0L container 0,25 mol of N₂ and 0,10 mol of O₂, concentrations in equilibrium will be:

[N₂] = 0,25M - x

[O₂] = 0,10M - x

[NO] = 2x

Replacing in (1):

[2X]² / [0,25-x] [0,10-x] = 4,10x10⁻⁴

[2X]² / 0,025 - 0,35x + x²= 4,10x10⁻⁴

4X² = 4,10x10⁻⁴x² - 1,435x10⁻⁴x + 1,025x10⁻⁵

3,99959x² + 1,435x10⁻⁴x - 1,025x10⁻⁵ = 0

Solving for x:

x = -0,0016 (Wrong answer, there is no negative concentrations)

x = 0,00158 (Right answer)

As molar concentration of NO in equilibrium is 2x:

[NO] = 2x = 2×0,00158 = 3,16x10⁻³M

I hope it helps!

6 0

4 years ago

Elements and compounds are 2 types of what?

GalinKa [24]

I think the answer is atoms.

3 0

3 years ago

Read 2 more answers

This is very urgent please hurry!!?!!??!

yawa3891 [41]

Answer:

The greatest acceleration when the unbalanced force is applied will be experienced in :

A) The box with a mass of 2 kg

Explanation:

According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.

F = (Final momentum - initial momentum)/time

or

Force is equal to the product of mass and acceleration

F = m x a

Here a= acceleration

m = mass of the object

If Force is constant then acceleration is inversely proportional to mass

$a =\frac{F}{m}$

A) The box with a mass of 2kg

F = 8 N

$a =\frac{8}{2}$

a = 4 m/s2

B) The box with the mass of 4kg

$a =\frac{8}{4}$

a = 2 m/s2

C) The box with a mass of 6kg

$a =\frac{8}{6}$

a = 1.33 m/s2

D) The box with a mass of 8kg

$a =\frac{8}{8}$

a = 1 m/s2

3 0

4 years ago

What is the mass, in grams, of

DIA [1.3K]

Answer:

The answers to your question are below

Explanation:

a) 6.85×1020 H2O2 molecules

H2O2 MW = 32 + 2 = 34 g

34g -------------------- 6.023 x 10²³ molecules

x ------------------- 6.85 x 10 ²⁰

x = (6.85 x 10 ²⁰)(34)/ 6.023 x 10²³

x = 0.038 g

3.3×1022 SO2 molecules

MW SO2 = 32 + 32 = 64g

64 g -------------------- 6.023 x 10²³ molecules

x -------------------- 3.3×1022 SO2 molecules

x = (3.3×1022 SO2)(64) / 6.023 x 10²³

x = 3.51 g

5.5×1025 O3 molecules

MW = 16 x 3 = 48g

48 g ----------------- 6.023 x 10²³ molecules

x ------------------ 5.5×1025 O3 molecules

x = (5.5×1025 )(48) / 6.023 x 10²³

x = 4383 g

9.30×1019 CH4 molecules

MW = 12 + 4 = 16 g

16 g -------------------- 6.023 x 10²³ molecules

x -------------------- 9.30×1019 CH4 molecules

x = (9.30×1019)(16) / 6.023 x 10²³

x = 0.0025 g

4 0

3 years ago