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andrezito [222]
3 years ago
5

Use the dichotomous key to identify these plant leaves.

Chemistry
1 answer:
CaHeK987 [17]3 years ago
6 0
There’s not a picture of a dichotomous key
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How many moles of NaOH are required to prepare 2.90 L of 1.8 M NaOH?
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V=2.90 L
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A chemist adds 135.0 mL of a 0.21M zinc nitrate (Zn(NO3) solution to a reaction flask. Calculate the mass in grams of zinc nitra
yKpoI14uk [10]

Answer:

5.36 grams the mass in grams of zinc nitrate the chemist has added to the flask.

Explanation:

Molarity=\frac{\text{Moles of solute}}{\text{Volume of the solution (L)}}

Moles of zinc nitrate = n

Volume of the solution = 135.0 mL = 0.1350 L

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0.21 M=\frac{n}{0.1350 L}

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Mass of 0.02835 moles of zinc nitrate:

0.02835 mol × 189 g/mol = 5.358 g ≈ 5.36 g

5.36 grams the mass in grams of zinc nitrate the chemist has added to the flask.

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