Option D.
A voltaic cell need tha anode, the cathode and the electrolyt to work.
Volitmeter is just an equipment to measure the functioning of the voltaic cell.
Answer: (a) The solubility of CuCl in pure water is
.
(b) The solubility of CuCl in 0.1 M NaCl is
.
Explanation:
(a) Chemical equation for the given reaction in pure water is as follows.

Initial: 0 0
Change: +x +x
Equilibm: x x

And, equilibrium expression is as follows.
![K_{sp} = [Cu^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCu%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)

x = 
Hence, the solubility of CuCl in pure water is
.
(b) When NaCl is 0.1 M,
, 
, 
Net equation: 
= 0.1044
So for, 
Initial: 0.1 0
Change: -x +x
Equilibm: 0.1 - x x
Now, the equilibrium expression is as follows.
K' = 
0.1044 = 
x = 
Therefore, the solubility of CuCl in 0.1 M NaCl is
.
Answer:
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Explanation:
Answer:
SiCl4 + H2O = SiO2 + HCl
Reactant. product
Si = 1 atom Si = 1 atom
Cl = 4 atom Cl = 1 atom
H = 2 atom H = 1 atom
O = 1 atom O = 2 atom
SiCl4. + 2H2o = SiO2 + 4hcl
Reactant. product
Si = 1 atom Si = 1 atom
Cl = 4 atom Cl = 4 atom
H = 4 atom H = 4 atom
O = 2 atom O = 2 atom
Balanced chemical equation.