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Vlad [161]
3 years ago
7

What is true about the structure or function of the plasma membrane?

Chemistry
1 answer:
den301095 [7]3 years ago
5 0

Answer: hi theree, the answer is c. the processes of endocytosis and exocytosis occur here

hope this helps, have a good day :)

Explanation:

You might be interested in
4. Explain error and how it can impact your results from an experiment
Jet001 [13]

Random errors will shift each measurement from its true value by a random amount and in a random direction. These will affect reliability (since they're random) but may not affect the overall accuracy of a result.

3 0
3 years ago
What are the disadvantages of aluminium fir building cars
Wittaler [7]

Disadvantages of aluminum in building cars include:

On average, aluminum is more expensive than steel, as much as two to three times.

Aluminum is not easily welded. If a steel door or panel suffers a crack, often it cam be welded back together easily, primed and repainted so its difficult to tell any body work has been performed. This cannot be done with aluminum. Steel  also can be bent and shaped as needed.

Body shops and even dealer service centers  are currently  equipped for steel work with technicians skilled in the art of welding and steel fabrication. The cost of switching over to an infra structure designed specifically for all-aluminum  vehicles or mass production of aluminum vehicles and components would be high.


4 0
4 years ago
What is the charge of the nucleus in an Adam of oxygen -17
Ivenika [448]
Charge of nucleus is always positive whether it is element or isotope.
5 0
3 years ago
Given the following data:
bagirrra123 [75]

176.0 \; \text{kJ} \cdot \text{mol}^{-1}

As long as the equation in question can be expressed as the sum of the three equations with known enthalpy change, its \Delta H can be determined with the Hess's Law. The key is to find the appropriate coefficient for each of the given equations.

Let the three equations with \Delta H given be denoted as (1), (2), (3), and the last equation (4). Let a, b, and c be letters such that a \times (1) + b \times (2) + c \times (3) = (4). This relationship shall hold for all chemicals involved.

There are three unknowns; it would thus take at least three equations to find their values. Species present on both sides of the equation would cancel out. Thus, let coefficients on the reactant side be positive and those on the product side be negative, such that duplicates would cancel out arithmetically. For instance, 3 + (-1) = 2 shall resemble the number of \text{H}_2 left on the product side when the second equation is directly added to the third. Similarly

  • \text{NH}_4 \text{Cl} \; (s): -2 \; a = 1
  • \text{NH}_3\; (g): -2 \; b = -1
  • \text{HCl} \; (g): 2 \; c = -1

Thus

a = -1/2\\b = 1/2\\c = -1/2 and

-\frac{1}{2} \times (1) + \frac{1}{2} \times (2) - \frac{1}{2} \times (3)= (4)

Verify this conclusion against a fourth species involved- \text{N}_2 \; (g) for instance. Nitrogen isn't present in the net equation. The sum of its coefficient shall, therefore, be zero.

a + b = -1/2 + 1/2 = 0

Apply the Hess's Law based on the coefficients to find the enthalpy change of the last equation.

\Delta H _{(4)} = -\frac{1}{2} \; \Delta H _{(1)} + \frac{1}{2} \; \Delta H _{(2)} - \frac{1}{2} \; \Delta H _{(3)}\\\phantom{\Delta H _{(4)}} = -\frac{1}{2} \times (-628.9)+ \frac{1}{2} \times (-92.2) - \frac{1}{2} \times (184.7) \\\phantom{\Delta H _{(4)}} = 176.0 \; \text{kJ} \cdot \text{mol}^{-1}

3 0
3 years ago
which types of intermolecular forces are most likely to dominate between large molecules containing long chains of carbon atoms
Serga [27]

Van der waals force

Explanation:

The intermoleclular forces are attraction between molecules. Interatomic forces are attraction between atoms in a compound.

In most hydrocarbons the weak Van der waals attraction are known.

  • These forces are weak attraction joining non-polar and polar molecules together.
  • These forces can also be found in layers of graphite.
  • They are of two types;

London dispersion forces are attraction that exists between non-polar molecules and the noble gas.

Dipole - Dipole attractions are forces of attraction existing in polar molecules.

In hydrocarbons, we have non-polar molecules and intermolecular attraction is london dispersion forces.

learn more:

Intermolecular forces brainly.com/question/10107765

#learnwithBrainly

6 0
4 years ago
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