Answer: 2.64 g of carbon dioxide that could be produced by the chemical reaction.
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of 
require = 2 moles of 
Thus 0.06 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 moles of give = 1 mole of 
Thus 0.06 moles of give =
of
Mass of 
Thus 2.64 g of carbon dioxide that could be produced by the chemical reaction.
Ionic bonds form bc of a difference in charges; opposites attract, negative to positive
4.7-5 litres :)
I just googled it sorry if it’s wrong ahahaha
Answer:
Explanation:
3BaCl₂(aq) + 2Na₃PO₄(aq) = Ba₃(PO₄)₂ + 6NaCl(aq)
3 x 208 g = 624 g 2 x 164 g = 328 g
328 g of Na₃PO₄ reacts with 624 g of BaCl₂
.611 g of Na₃PO₄ reacts with 624 x .611/328 g of BaCl₂
624 x .611/328 g = 1.16 g of BaCl₂
BaCl₂ available is .504 g which is less than required .
Hence BaCl₂ is limiting reagent .
