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OlgaM077 [116]
3 years ago
15

Please help ASAP...A satellite takes 24 hours to complete one orbit whilst travelling at a speed of 12 km/s. at what height abov

e the earth is the satellite orbiting. Thank you :)
Physics
1 answer:
Darya [45]3 years ago
8 0
By mentioning space, satellites, and orbits, the question is trying to convince you that your brain can't operate because there is no oxygen. Try thinking about the question this way: If it takes you 24 hours to travel around a circle, at the speed of 12 km/sec, then what's the radius of the circle ?
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What are the methods of heat transfer? ​
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Answer:

Radiation , Conduction and Convection

Explanation:

Those are the ways heat is transferred

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As a 3.0 kg bucket is being lowered into a 10 m deepwell, starting from top, the tension in the rope is 9.8 N. theacceleration o
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Answer:

A) 6.5 m/s²

Explanation:

Mass of the bucket, m = 3.0 kg

depth of the well, d = 10 m

tension on the rope, T = 9.8 N

The net downward force on the bucket is given as;

T = mg - ma

where;

a is downward acceleration of the bucket

9.8 = (3 x 9.8) - 3a

9.8 = 29.4 - 3a

3a = 29.4 - 9.8

3a = 19.6

a = 19.6 / 3

a = 6.53 m/s² downwards

Therefore, the acceleration of the bucket is 6.53 m/s² downwards

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Which list places the layers of the sun in the correct order from outermost to innermost?
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Is D

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3 years ago
A moving object with a decreasing velocity covers distance during
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The answer is C. Less
8 0
3 years ago
An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remai
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Answer:

The runner's speed at the following times would remain 8.64 m/s.

Explanation:

Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.

In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.

First equation of motion:        Vf = Vi + a×t

Vf stands for final velocity

Vi stands for initial velocity

a stands for acceleration

t stands for time

In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.

The acceleration (a) is given as 2.4 m/s²

The time (t) is given as 3.6 s

Now put the values of Vi, a and t in first equation of motion

                       Vf = Vi + a×t

                       Vf = 0 + 2.4×3.6

                       Vf = 2.4×3.6

                       Vf = 8.64 m/s

So,the runner's speed at the following times would remain 8.64 m/s.

5 0
3 years ago
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