Please help ASAP...A satellite takes 24 hours to complete one orbit whilst travelling at a speed of 12 km/s. at what height abov
1 answer:
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Answer:
(a). The draw-down at a distance 200 m from the well after pumping for 50 hr is 5.383 m.
(b). The draw-down at a distance 200 m from the well after pumping for 50 hr is 6.707 m.
Explanation:
Given that,
Energy
Transmissivity
Storage coefficient
Distance r= 200 m
We need to calculate the draw-down at a distance 200 m from the well after pumping for 50 hr
Using formula of draw-down
Put the value into the formula
We need to calculate the draw-down at a distance 200 m from the well after pumping for 200 hr
Using formula of draw-down
Put the value into the formula
Hence, (a). The draw-down at a distance 200 m from the well after pumping for 50 hr is 5.383 m.
(b). The draw-down at a distance 200 m from the well after pumping for 200 hr is 6.707 m.
Answer:
total work is = 52450 J
Explanation:
given data
mass = 5000-lb
density = 10 lb/ft
height = 50 ft
solution
as we will treat here cable and ball are separate
and
here work need to lift cable is
w = (10Δy )(9.8 y ) j
and
now summing all segment of cable
so passing limit Δy to 0
so total work need
=
=
= 2450J
so lifting 5000 lb wrcking 50 m required additional 5000 + 2450
so total work is = 52450 J