The mole fraction of KCl in the solution is 0.1051
calculation
mole fraction of KCl in solution = moles of KCl / total number of moles(moles of KCl +moles of H2O)
moles=mass/molar mass
mass of KCl=32.7g
molar mass of KCl= 39 +35.5
moles of KCl is therefore= 32.7g/74.5 g/mol=0.439 moles
find the moles of H2O= mass of H2O/molar mass
mass of H2O=100-32.7=67.3g
molar mass of H2O=( 1 x2) +16=18 g/mol
moles = 67.3/18 =3.739 moles
total moles=3.739+0.439=4.178 moles
mole fraction is therefore=0.439/4.178=0.1051
Answer:
Judging from the wording of he question, you mean units. If that is indeed the case, the answer is g/Mol (grams per mol)
Let me know if my interpretation is incorrect and please tell me what you are actually trying to find.
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Answer:
Explanation:
- MgO = __2__ atoms
2- Rb2S = __3__ atoms
3- Ca(OH)2 = __5__ atoms
4- K2SO4 = __7__ atoms
5- Ga2(CO3)2 = __10__ atoms
Answer: Thus 44 g of 
will be produced if 30 g of 
were reacted with an excess of oxygen
Explanation:
To calculate the moles :
The balanced chemical equation is:
As is the limiting reagent as it limits the formation of product and 
is the excess reagent.
According to stoichiometry :
1 mole of produce = 6 moles of
Thus 0.17 moles of will produce=
of
Mass of 
Thus 44 g of will be produced if 30 g of were reacted with an excess of oxygen.
