All categories

3 years ago

So What Happens to the Body When We Warm. Up?

Chemistry

1 answer:

tatyana61 [14]3 years ago

7 0

Answer:

Option 1.

Explanation:

When we warm up, our heart rate increases and we require much more energy to continue. Hence, our body absorbs much more oxygen from the surroundings, digest food and etc.

Sorry if the explanation might sound wrong, I learned this during science 2 years ago so I forgot.

You might be interested in

Describe the nuclear model of the atom

gulaghasi [49]

An atom consist of mainly two parts, namely nucleus and electrons. In the nucleus, there are groups of protons and neutron DENSELY packed, each element has its own atomic number(number of protons) but can have different no. of neutron (isotop). within the proton and neutron, there are subatomic particles called quarks. Talking about the electrons, they move very quickly arround the nucleus and there are different energy level for electron to switch between. In chemical reaction, we are only concerning the no. of valence electrons.
Can you follow me and like me please?

7 0

3 years ago

I Need help with this worksheet I Need the Work Please Thank you

Komok [63]

1. a. 3

b. 2

2. a. 4

b. 6

3. a. 1

b. 2

4. a. 5

4 0

2 years ago

The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:

aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium: 0.50M - x x x

The equilibrium constant (Ka₁) is:

$K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}$

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

$[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M$

Similarly, from the second dissociation of sulfurous acid we have:

HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium: 7.94x10⁻²M - x x x

The equilibrium constant (Ka₂) is:

$K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}$

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

$[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M$

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0

3 years ago

Gold is formed in pure state in nature but not iron,why?

ss7ja [257]

Gold is found in pure state in nature but not the iron because gold is un-reactive metal, so it does not react with other element in normal condition but iron is reactive metal so it reacts with atmospheric oxygen in presence of moist (water) to form oxide.

Explanation:

I hope it'll help you.

5 0

3 years ago

Read 2 more answers

What is the weighted average of a nail in the sample data given?

Natalka [10]

The weighted average of the nail in accordance with the given data is 11.176g.

<h3>How to calculate weighted average?</h3>

Weighted average is an arithmetic mean of values biased according to agreed weightings.

The weighted average of the nail in the image above can be calculated by multiplying the decimal abundance with the mass of the nail, then summed up as follows;

Weighted average = (decimal abundance × mass 1) + (decimal abundance × mass 2)

Weighted average = (0.12 × 3.3) + (0.88 × 12.25)

Weighted average = 0.396 + 10.78

Weighted average = 11.176g

Therefore, 11.176g is the weighted average of the nail

Learn more about weighted average at: brainly.com/question/28042295

#SPJ1

5 0

1 year ago