Does energy generation through a wind generator seem to depend more on potential or kinetic energy? Explain.

A car’s velocity as a function of time is given by Vx (t) = α.t + β.t 2 , where α= 3m/s and β= 0.1m/s 3 . Calculate the average

s344n2d4d5 [400]

The definition of average acceleration allows to find the result for the average acceleration in the given time interval is:

$a_{average}= 1.5 \ \frac{m}{s^2}$

Instantaneous acceleration is defined as the derivative of velocity with respect to time.

a = $\frac{dv}{dt}$

Where a is the acceleration, v the velocity and t the time.

They indicate that the speed of the car is given by the relation.

v = α t + β t²

With α = 3 m / s and β = 0.1 m / s³

Let's make the derivative.

a = α + 2β t

Let's substitute

a = 3 + 2 0.1 t

Average acceleration is the change in velocity in the time interval.

$a_{average} = \frac{\Delta v}{\Delta t }$

Let's find the velocity at the indicated time.

For t = 5 s

v₅ = 3 + 0.1 5²

v₅ = 5.5 m / s

For t = 10 s

v₁₀ = 3 + 0.1 10²

v₁₀ = 13 m / s

Let's calculate the average acceleration.

$a_{average} = \frac{13 - 5.5 }{ 10 - 5 }\\$

$a_{average}= 1.5 \ m/s^2$

In conclusion using the definition of mean acceleration we can find the result for the mean acceleration in the given time interval is:

$a_{average} =$ 1.5 m / s²

Learn more here: brainly.com/question/20057878

7 0

3 years ago

When a police officer catches you speeding by using a radar gun, the waves sent out by the gun must be _______ off your car.

Neporo4naja [7]

I would say its Absorbed

7 0

3 years ago

An astronaut is being tested in a centrifuge. The centrifuge has a radius R and, in starting, rotates according to θ = tn, where

Igoryamba

Answer:

a) ω=n

b) V = R*n

c) a = 0

d) $ar = R*n^2$

Explanation:

Angular velocity is given by the derivative of θ:

ω = n

Linear Velocity will be:

V = ω*R = n*R

Tangential acceleration will be the derivative of the linear velocity. Since velovity is constant:

a = 0

Radial acceleration is given by:

$ar = V^2/R = (R*n)^2/R=R*n^2$

4 0

4 years ago

Write the following numbers in proper scientific notation:

ipn [44]

Answer:

0.00050, 0.000000000406, 36513

4 0

4 years ago

A 2.0-m length of wire is made by welding the end of a 120-cm-long silver wire to the end of an 80-cm long copper wire. Each pie

brilliants [131]

Answer:a). 97.2A b). 97.2A c). 5.85V/m d). 3.6V/m

e). 4.68V

Explanation:

Silver has a resistivity of 1.59e−8 Ω-m.

Copper has a resistivity of 1.68e−8 Ω-m.

Each wire is 0.60 mm in diameter or 0.30 mm in radius, giving a cross-sectional area of πr², or 2.83e-7 m² (note conversion from mm to m). Divide the resistivity by this number to get each wire's resistance per meter. Then multiply by the length of the wire to get the actual resistance:

Silver: (1.59e−8 Ω-m)(0.80 m) / (2.83e-7 m²) = 0.0450 Ω

Copper: (1.68e−8 Ω-m)(0.80 m) / (2.83e-7 m²) = 0.0475 Ω

Total resistivity: 0.0925 Ω (just the sum of the two wires)

Now that we know the resistance of each wire, we can easily answer the problems.

A) The current through the wires is found from Ohm's Law, V=IR. Solving for I gives:

I = V/R = (9.0 V) / (0.0925 Ω) = 97.2A

This same current passes through both wires, of course; any current passing through one wire must pass through the other.

B) I = 97.2A ( same as above)

C) Electric field strength E is measured in volts/meter. It is found by determining the voltage drop across a given length. For the 0.80-m long copper wire, the voltage drop is proportional to the copper wire's resistance. That is,

R(copper)/R(total) = V(copper)/V(total)

So

V(copper) = V(total) R(copper) / R(total)

= (9.0 V) (0.0475 Ω) / (0.0925 Ω)

= 4.68 V

Therefore, the total electric field E in the copper wire is

E(copper) = V(copper) / length(copper)

= (4.68V) / (0.80 m)

= 5.85 V/m

D) V(silver) = V(total) - V(copper)

= 9.0 V - 4.68 V

= 4.32 V

Thus,

E(silver) = V(silver) / length(silver)

= (4.32 V) / (1.2 m)

= 3.6 V/m

E) Already calculated in (C) =4.68V

7 0

3 years ago