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kirza4 [7]
2 years ago
10

2) What group of elements are most likely to react with helium? Explain why.

Chemistry
1 answer:
Luba_88 [7]2 years ago
7 0

Answer:

Helium does not react with any element

Please find the explanation below

Explanation:

Helium (He) is an element in group 8A of the periodic table, which is a group of element referred to as NOBLE GASES. Other elements in this group are Xenon (Xe), Krypton (Kr), Neon (Ne) etc.

One major characteristics of Helium and other Noble gases that makes them so UNREACTIVE is that they have a full electronic configuration i.e. they have a full electron shell and do not share electrons with any element, which is the basis of REACTING. For this reason, Helium will not react with any element.

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Answer: first blank is heating second blank is pressure i think but i know that its NOT freezing

Explanation:

I did it and got it right

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Which of the following is a synthesis reaction?
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What is the molarity of 122.5 g of AlCl3 in 1.0 L of solution? (MM = 133 g/mol)
yawa3891 [41]
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4 0
3 years ago
Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0
3 years ago
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