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kirza4 [7]
3 years ago
10

2) What group of elements are most likely to react with helium? Explain why.

Chemistry
1 answer:
Luba_88 [7]3 years ago
7 0

Answer:

Helium does not react with any element

Please find the explanation below

Explanation:

Helium (He) is an element in group 8A of the periodic table, which is a group of element referred to as NOBLE GASES. Other elements in this group are Xenon (Xe), Krypton (Kr), Neon (Ne) etc.

One major characteristics of Helium and other Noble gases that makes them so UNREACTIVE is that they have a full electronic configuration i.e. they have a full electron shell and do not share electrons with any element, which is the basis of REACTING. For this reason, Helium will not react with any element.

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A zinc rod is placed in 0.1 MZnSO4 solution at 298 K. Write the electrode reaction and calculate the potential of the electrode.
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<u>Answer:</u> The potential of electrode is -0.79 V

<u>Explanation:</u>

When zinc is dipped in zinc sulfate solution, the electrode formed is Zn^{2+}(aq.)/Zn(s)

Reduction reaction follows:  Zn^{2+}(0.1M)+2e^-\rightarrow Zn(s);(E^o_{Zn^{2+}/Zn}=-0.76V)

To calculate the potential of electrode, we use the equation given by Nernst equation:

E_{(Zn^{2+}/Zn)}=E^o_{(Zn^{2+}/Zn)}-\frac{0.059}{n}\log \frac{[Zn]}{[Zn^{2+}]}

where,

E_{cell} = electrode potential of the cell = ?V

E^o_{cell} = standard electrode potential of the cell = -0.76 V

n = number of electrons exchanged = 2

[Zn]=1M    (concentration of pure solids are taken as 1)

[Zn^{2+}]=0.1M

Putting values in above equation, we get:

E_{cell}=-0.76-\frac{0.059}{2}\times \log(\frac{1}{0.1})\\\\E_{cell}=-0.79V

Hence, the potential of electrode is -0.79 V

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What must be changed, temperature or heat energy, during condensation explain in 2-3 sentences
Nastasia [14]

Answer:

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Explain the difference between a base unit and a derived unit
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Free_Kalibri [48]

Answer:

The molar mass and molecular weight of Sn(CO3)2 is 238.728.

Explanation:

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