Answer:
A. Inertial Confinement and B. Magnetic Confinement
Answer:
The net Electric field at the mid point is 289.19 N/C
Given:
Q = + 71 nC = 
Q' = + 42 nC = 
Separation distance, d = 1.9 m
Solution:
To find the magnitude of electric field at the mid point,
Electric field at the mid-point due to charge Q is given by:
Now,
Electric field at the mid-point due to charge Q' is given by:
Now,
The net Electric field is given by:
Answer:
x2 = 64 revolutions.
it rotate through 64 revolutions in the next 5.00 s
Explanation:
Given;
wheel rotates from rest with constant angular acceleration.
Initial angular speed v = 0
Time t = 2.50
Distance x = 8 rev
Applying equation of motion;
x = vt +0.5at^2 ........1
Since v = 0
x = 0.5at^2
making a the subject of formula;
a = x/0.5t^2 = 2x/t^2
a = angular acceleration
t = time taken
x = angular distance
Substituting the values;
a = 2(8)/2.5^2
a = 2.56 rev/s^2
velocity at t = 2.50
v1 = a×t = 2.56×2.50 = 6.4 rev/s
Through the next 5 second;
t2 = 5 seconds
a2 = 2.56 rev/s^2
v2 = 6.4 rev/s
From equation 1;
x = vt +0.5at^2
Substituting the values;
x2 = 6.4(5) + 0.5×2.56×5^2
x2 = 64 revolutions.
it rotate through 64 revolutions in the next 5.00 s
Answer:
t = 8.33 minutes
Explanation:
given,
Speed of Light, v = 3 x 10⁸ m/s
distance between sun to Earth = 1.5 x 10¹¹ m
time taken to reach earth = ?
we know,
Distance = speed x time
t = 500 s
1 min = 60 s
now, 
t = 8.33 minutes
time taken by the light to reach earth is equal to 8.33 minutes.
Answer:
(1) 2.25m/s^2
(2) 45.6m
Explanation:
(1) A car accelerates uniformly from 12m/s to 39m/s in 12 seconds
Therefore the average acceleration can be calculated as follows
a = 39-12/12
a = 27/12
a= 2.25m/s^2
(2) A butterfly is flying at 4m/s , it accelerates uniformly at 1.2 m/s for 6 seconds
u= 4
a= 1.2
t= 6
Therefore the distance can be calculated as follows
S= ut + 1/2at^2
= 4×6 + 1/2 × 1.2 × 6^2
= 24 + 1/2 × 1.2 × 36
= 24 + 1/2 × 43.2
= 24 + 21.6
S = 45.6m
Hence the butterfly travels at 45.6m
