All categories

3 years ago

Select the Independent, Dependent and Controlled Variables

Chemistry

2 answers:

Maru [420]3 years ago

6 0

Answer:

The independent variable is graphed on the x-axis. The dependent variable, which changes in response to the independent variable, is graphed on the y-axis. Controlled variables are usually not graphed because they should not change.

Explanation:

dalvyx [7]3 years ago

4 0

Answer:

You might be interested in

What happens to an object at rest if balanced forces act upon it?

OLga [1]

Newton's first law of motion states that an object at rest will remain at rest unless an unbalanced force acts on it. If you apply balanced forces on the object there would be no net force. The body does not accelerate but instead stays at rest.

Another way to look at this problem is to use Newton's second law of motion. The first law states that $F = m\times a$ , where $a$ is the acceleration $F$ is the net force and $m$ is the mass of the object.

When F is zero, the acceleration of the object is zero. This means that if the object had a velocity of zero before the balanced forces started acting, the velocity will stay at zero after the balanced forces begin to act. If the object was moving at a constant velocity before the balanced forces started acting on it, it would continue at that constant velocity after the balanced forces begin to act.

4 0

3 years ago

- Standard state refers to

yulyashka [42]

Answer: The standard state refers to 1 atm and $25^{o}C$ .

Explanation:

It is known that a chemical/substance can either be present in a solid, liquid or gaseous state.

So, when the phase of a substance like solid, liquid or gas is present at 1 atmosphere pressure and at a temperature of $25^{o}C$ then it known as standard state of substance.

Thus, we can conclude that standard state refers to 1 atm and $25^{o}C$ .

4 0

3 years ago

If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equa

Genrish500 [490]

If the length of a string increases 2 times but the mass of the string remains constant, the original density will be multiplied by a factor mathematically given as

v=1.414 times

<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>

Generally, the equation for the volume is mathematically given as

v = sqt(TL/m)

Where

density = mass/length

Therefore

$v2/v1 = \sqrt{L2/L1}$

$v2/v1 = \sqrt{2}$

In conclusion,v ratio will give us

v=1.414 times