Yes I can help jus tell me what the 26th question is
(a) As the car is moving with constant velocity, it means the rate change of velocity does not change, therefore the average acceleration of the car is zero.
Thus, there is no acceleration, when velocity is constant.
(b) Average acceleration,

Here, v is final velocity and u is the initial velocity and
is the time interval.
As twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed, therefore

Thus, the average acceleration of the car is
in the direction to the left.
Answer:
T - M g - Ff = M a describes the acceleration of the object
T = M g + Ff if the object moves at constant speed (a = zero)
Ff = μ M g = .3 * 40 * 9.8 = 118 N the force of friction
Ff will be in a direction opposite to the motion
M g = 40 kg * 9.8 m/s = 392 N
a) T = M g + Ff for an object moving upwards
T = 392 + 118 = 510 N
b) T = M g - Ff for an object moving downwards
T = 392 - 118 = 274 N
By the law of reflection which says that the angle of reflection is equal to the angle of incidence, which in other words says, sin x = sin y, it can be said, based on the given that the angle of reflection is also equal to the angle of incidence of 35 degrees