The answer is A. every sec means a mile.hope this helped
Answer:
Vb = v/2
Half of the speed of Car A before the collision
Explanation:
This problem can be solved by using conservation of momentum.

Since car B was stopped before the collision and its mass is twice the mass of A:

Also, since it is an elastic collision, car A stops after hitting car B. Rewriting the equation:

Therefore, the speed of car B after the collision is half of the speed of car A before the collision (v)
Vb = v/2
Answer:
V₀ₓ = 9.2 m/s
Nearest answer:
D) 8.9 m/s
Explanation:
First we find the time taken by the pumpkin to hit the car. For that purpose we apply 2nd equation of motion to the pumpkin:
h = V₀y t + (1/2)gt²
where,
h = height of building = 10.4 m
V₀y = vertical component of initial speed = 0 m/s
t = time = ?
g = 9.8 m/s²
Therefore,
10.4 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²
t² = (10.4 m)(2)/(9.8 m/s²)
t = √[2.122 s²]
t = 1.45 s
Now, we analyze horizontal motion for horizontal component of initial velocity. We assume air friction to be zero so that the horizontal motion is uniform. Therefore,
s = V₀ₓ t
where,
s = horizontal distance between building and car = 13.4 m
V₀ₓ = Horizontal Component of Initial Velocity = ?
Therefore,
13.4 m = V₀ₓ(1.45 s)
V₀ₓ = 13.4 m/1.45 s
<u>V₀ₓ = 9.2 m/s</u>
In this item if we let x be the number of doubling period, that is number of days divided by 3, and y be the height of the bamboo shoot, in the equation
y = ab^x
The value of a is 5 because that is the original height of the shoot and b is 2 because we are talking about the doubling rate. The equation is therefore,
y = 5(2^x)
Answer:
B.1.6 N*s
Explanation:
According to the principle of conservation of momentum, we have:

The final mass is obtained adding the masses of the two cars since they stick together after the collision. So,
. Recall that the 0.4 kg cart collides with the stationary 0.8-kg cart. So 

The magnitude of the impulse is defined as the mass multiplied by the change in the speed:
