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matrenka [14]
3 years ago
6

Are we within earths Roche limit

Physics
1 answer:
Sergeu [11.5K]3 years ago
3 0

Answer: Closer to the Roche limit, the body is deformed by tidal forces. Within the Roche limit, the mass' own gravity can no longer withstand the tidal forces, and the body disintegrates. hope this helps can u give me brainliest

Explanation:

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A blue ball is thrown upward with an initial speed of 24.1 m/s, from a height of 0.5 meters above the ground. 2.9 seconds after
Aleks04 [339]

Answer:

1. Speed=0

2. 2.46 s

3.30.1 m

4. 22.0 m

5.1.004 s

Explanation:

We are given that

Initial speed of blue ball, u=24.1 m/s

Height of blue ball from ground y_0=0.5 m

Initial speed of red ball , u'=7.2 m/s

Height of red from ground=y'0=32 m

Gravity, g=9.81ms^{-2}

1.When the ball reaches its maximum height then the speed of the blue ball is zero.

2.v=0

v=u+at

Using the formula and substitute the values

0=24.1-9.81t

Where g is negative because motion of ball is against gravity

24.1=9.81t

t=\frac{24.1}{9.81}=2.46s

3.y=y_0+ut+\frac{1}{2}at^2

Using the formula

y=0.5+24.1(2.46)-\frac{1}{2}(9.81)(2.46)^2

y=30.1 m

4.Time of flight for red ball=3.77-2.9=0.87s

y'=32-7.2(0.87)-\frac{1}{2}(9.81)(0.87)^2

y'=22.0m

Hence, the height of red ball 3.77 s after the blue ball is 22.0 m.

5.According to question

0.5+24.1(t+2.9)-\frac{1}{2}(9.81)(2.9+t)^2=32-7.2t-\frac{1}{2}(9.81)t^2

0.5+24.1t+69.89-4.905(t^2+5.8t+8.41)=32-7.2t-4.905t^2

0.5+24.1t+69.89-4.905t^2-28.449t-41.25105=32-7.2t-4.905t^2

0.5+69.89-41.25105-32=-24.1t+28.449t-7.2t

-2.86105=-2.851t

t=\frac{2.86105}{2.851}=1.004 s

Hence,  1.004 s  after the blue ball is thrown  are the two balls in the air at the same height.

8 0
3 years ago
What is the intensity of a sound with a sound intensity level (SIL) 67 dB, in units of W/m^2?
vfiekz [6]

Answer:

The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²

Explanation:

We have expression for sound intensity level (SIL),

              L=10log_{10}\left ( \frac{I}{I_0}\right )

Here we need to find the intensity of sound (I).

               L=10log_{10}\left ( \frac{I}{I_0}\right )\\\\log_{10}\left ( \frac{I}{I_0}\right )=0.1L\\\\\frac{I}{I_0}=10^{0.1L}\\\\I=I_010^{0.1L}

Substituting

          L = 67 dB and I₀ = 10⁻¹² W/m² in the equation

          I=I_010^{0.1L}=10^{-12}\times 10^{0.1\times 65}\\\\I_0=10^{-12}\times 10^{6.5}=10^{-5.5}=3.16\times 10^{-6}W/m^2

The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²

8 0
3 years ago
Take the regular compass and hold it so the case is vertical. Now use it to investigate the direction of the coil’s magnetic fie
Sliva [168]

Answer:

Please find the answer in the explanation

Explanation:

Take the regular compass and hold it so the case is vertical. Now use it to investigate the direction of the coil’s magnetic field at locations other than the central axis.

What happens as you move away from the center axis toward the coil? The direction of the magnetic compass needle will move in an opposite direction since the direction of the induced voltage is reversed.

What happens above the coil?

the needle on the magnetic compass will be deflected. Since compasses work by pointing along magnetic field lines

Outside the coil? The magnetic compass needle will experience no deflection. Since there is no induced voltage or current.

Below the coil?

The needle will move in an opposite direction.

3 0
3 years ago
If Jeff is sitting in a gaming rocker chair reading instructions is any work being done
Mazyrski [523]
Yes, while he is sitting he is reading something to prepare him to finsh a job. reading instructions can be considered step one in starting a job. ex-before builders are able build, they must read the blueprints in order to know what to do. 
5 0
4 years ago
Un móvil que viaja a 40 m/s aplica los frenos y desacelera a razón de -0,25 m/seg 2 , ¿Cuánto tiempo le llevo
aivan3 [116]

Answer:

Where is a picture?

Explanation:

4 0
3 years ago
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