Answer:
a1 = (V2 - V1) / 1 s = 3.75 m/s^2
a2 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2
a3 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2
A) a = (a1 + a2 + a3) / 3 = 3.75 m/s^2
v = a (t2 - t1)
B) after 1 sec v = 3.75 m / sec^2 * 1 sec = 3.75 m/s
after 2 sec v = v0 + a t = 3.75 m/s + 3.75 m/s^2 * 1 s = 7.5 m/s
C) The velocity increases proportionaly to the time
D) One factor depends on the variation of the acceleration due to gravity because of different positions of measurement (on earth)
A much larger factor is due to air resisance of the air on the falling object
Answer:
Required charge 
.
Explanation:
Given:
Diameter of the isolated plastic sphere = 25.0 cm
Magnitude of the Electric field = 1500 N/C
now
Electric field (E) is given as:
where,
k = coulomb's constant = 9 × 10⁹ N
q = required charge
r = distance of the point from the charge where electric field is being measured
The value of r at the just outside of the sphere = 
thus, according to the given data
or
or
Required charge .
Now,
the number of electrons (n) required will be
or
or
B and C because an earthquake does not directly affect gravity, and precipitation doesn’t fall, it is water surfacing
Answer:
what is your question because I seem to not see a question in this question....
