Answer:
the force acting on the team mate is 1.19 kN.
Explanation:
given,
mass = 196 lbm
while tackling, the deceleration is from velocity 6.7 m/s to 0 m/s
time taken for deceleration = 0.5 sec
F = mass × acceleration
acceleration = 
= -13.4 m/s²
1 lbs = 0.453 kg
196 lbs = 196 × 0.453 = 88.79 kg
F = 88.79 × 13.4
F = 1189.786 N = 1.19 kN
hence, the force acting on the team mate is 1.19 kN.
Since the density of the substance is ρ (rho),
==> every cm³ of this substance has ρ grams of mass.
Then
==> V cm³ of it has ρV grams of mass. That's ' m '.
and
==> 3V cm³ of it has 3ρV grams of mass. That's ' <em>3m</em> '.
Answer:
2000 mili ampere
Explanation:
1 ampere is = to 1000 miliampere so 2 x 1000 is equal to 2000 miliampere
Answer:
2KI + Cl₂ → 2KCl + I₂
Explanation:
The reaction equation is given as:
KI + Cl₂ → KCl + I₂
The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;
aKI + bCl₂ → cKCl + dI₂
Conserving K : a = c
I : a = 2d
Cl : 2b = c
Now let a = 1, c = 1 , d = 
, b = , ;
Multiply through by 2;
a = 2, b = 1 , c = 2, d = 1
2KI + Cl₂ → 2KCl + I₂
Answer:
Final speed of the ball = Vf= 12.52 m/s when it hits the ground
Explanation:
Height = S= 8.0 m
Initial Velocity= Vi = 0 m/s
Final Velocity= Vf =?
Acceleration due to gravity= a=9.8m/s²
Using Newtons third equation of motion
2as= Vf²- Vi²
2(9.8) 8= Vf²- 0
156.8= Vf²
Vf=√156.8= 12.52m/s
Final Speed of the ball is 12.52 m/s
