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3 years ago

How can we protect space shuttles or astronauts from space radiation in the absence of the atmospheric layer?

1 answer:

7 0

Earth's protective magnetic bubble, called the magnetosphere, deflects most solar particles, but in the absence of atmospheric layer, Polyethylene is a good shielding material because it has high hydrogen content, and hydrogen atoms are good at absorbing and dispersing radiation.

The Earth’s atmospheres are kept in place by gravity. The air near the ground is pulled on by gravity and compressed by the air higher in the sky. This causes the air near the ground to be denser and creating different layers with different qualities in which are the atmosphere.

Hope that helps ^^

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What mass of water must evaporate from the skin of a 70.0 kg man to cool his body 1.00 ∘C? The heat of vaporization of water at

romanna [79]

Answer:

100 cc

Explanation:

Heat released in cooling human body by t degree

= mass of the body x specific heat of the body x t

Substituting the data given

Heat released by the body

= 70 x 3480 x 1

= 243600 J

Mass of water to be evaporated

= 243600 / latent heat of vaporization of water

= 243600 / 2420000

= .1 kg

= 100 g

volume of water

= mass / density

= 100 / 1

100 cc

1 / 10 litres.

6 0

2 years ago

Para que exista una fuerza se necesita cuando menos…

kozerog [31]

Answer:

Explanation:

No entiendo lo que quieres decir con eso

8 0

3 years ago

The moon does not have atmosphere. Why?

Galina-37 [17]

Answer: It doesn't because it's not that big.

Explanation:

6 0

3 years ago

Read 2 more answers

One of the many by products of uranium is radioactive plutonium, which has a half life of approximatley 25000 ytears. if some of

strojnjashka [21]

Answer:

0.9972 fraction of plutonium will remain after 100 years.

Explanation:

Half life of plutonium = $t_{1/2}=25000 years$

Let the initial mass of plutonium be = $A_o$

Mass of plutonium after time of 100 years = A

Decay constant for this process = $\lambda =\frac{0.693}{t_{1/2}}$

$A=A_o\times e^{-\lambda t}$

$A=A_o\times e^{-\frac{0.693}{25000 years}\times 100 year}$

$A=A_o\times 0.9972$

$\frac{A}{A_o}=0.9972$

0.9972 × 100 = 99.72 %

0.9972 fraction of plutonium will remain after 100 years.

8 0

3 years ago

______ involves the use of electronic equipment to verify that an offender is at home or in a community correctional center duri

erastova [34]

Answer:

Remote Location Monitoring

Explanation:

Remote Location Monitoring involves the use of electronic equipment to verify that an offender is at home or in a community correctional center during specified hours o to track his her whereabouts.

Using programmed contact to verify an offenders location that distant, varied by the use of Global positioning system (GPS) to continuously map the exact location of the offender.

3 0

2 years ago