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OleMash [197]
3 years ago
14

When trying to clean muddy, dirty river water, which method would work

Chemistry
1 answer:
Llana [10]3 years ago
6 0
When trying to clean muddy, dirty river water, FILTRATION would work best
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A. Convert the mass of the Salt weighed out to fg.
omeli [17]

Answer:

6.564×10¹⁶ fg.

Explanation:

The following data were obtained from the question:

Mass of beaker = 76.9 g

Mass of beaker + salt = 142.54 g

Mass of salt in fg =?

Next, we shall determine the mass of the salt in grams (g). This can be obtained as follow:

Mass of beaker = 76.9 g

Mass of beaker + salt = 142.54 g

Mass of salt =?

Mass of salt = (Mass of beaker + salt) – (Mass of beaker)

Mass of salt = 142.54 – 76.9

Mass of salt = 65.64 g

Finally, we shall convert 65.64 g to femtograms (fg) as illustrated below:

Recall:

1 g = 1×10¹⁵ fg

Therefore,

65.64 g = 65.64 g × 1×10¹⁵ fg / 1g

65.64 g = 6.564×10¹⁶ fg

Therefore, the mass of the salt is 6.564×10¹⁶ fg.

3 0
3 years ago
What are chemical formulaes?<br> give your own response!!
lbvjy [14]

Answer:

is a way of presenting information about the chemical proportions of atoms

Explanation:

8 0
3 years ago
Even when an object appears to be at rest, its atoms and molecules are in constant motion
natita [175]

Answer:

the answer is True

Explanation:

the answer is True

5 0
2 years ago
is the metal clip on the seatbelt in the summertime have a higher specfic heat or does the fabric on the seat belt?
SOVA2 [1]
Yes because metal is more attracted to heat from the sun
5 0
3 years ago
The pressure in an automobile tire filled with air is 245.0 kPa. If Po2 = 51.3 kPa, Pco2 = 0.10 kPa, and P-others = 2.3 kPa, wha
Kay [80]

Answer:

PN₂ = 191.3 Kpa

Explanation:

Given data:

Total pressure of tire = 245.0 Kpa

Partial pressure of PO₂ = 51.3 Kpa

Partial pressure of PCO₂  = 0.10 Kpa

Partial pressure of others =  2.3 Kpa

Partial pressure of PN₂ = ?

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this  problem by using this law.

P(total) = PO₂ + PCO₂ + P(others)+ PN₂

245 Kpa = 51.3 Kpa + 0.10 Kpa + 2.3 Kpa + PN₂

245 Kpa = 53.7 Kpa+ PN₂

PN₂ = 245 Kpa -  53.7 Kpa

PN₂ = 191.3 Kpa

6 0
3 years ago
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