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2 years ago

9

Write a chemical equation for the following reaction. (Type your answer using format CH4 for CH4.) In water, iron(III) chloride

reacts with sodium hydroxide, producing solid iron(III) hydroxide and sodium chloride.

1 answer:

taurus [48]2 years ago

7 0

Answer:

FeCl3(aq) -

3NaOH(aq) 0 Fe(OH)3(s) -

3NaCl(aq)

Explanation:

FeCl3(aq) -

3NaOH(aq) 0 Fe(OH)3(s) -

3NaCl(aq)

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a laboratory procedure calls for making 510.0 mL of a 1.6 M KNO3 solution. How much KNO3 in grams is needed

barxatty [35]

Answer:

82.416 g of KNO ₃ is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Explanation:

Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?

$moles=\frac{510 mL*1.6 moles}{1000 mL}$

moles= 0.816

Being the molar mass of the elements:

K: 39 g/mole
N: 14 g/mole
O: 16 g/mole

So the molar mass of the compound KNO₃ is:

KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?

$mass=\frac{0.816 moles*101 grams}{1 mole}$

mass= 82.416 grams

<u><em>82.416 g of KNO ₃ is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.</em></u>

4 0

2 years ago

Deep sea divers use a mixture of helium and oxygen to breathe. Assume that a diver is going to a depth of 150 feet where the tot

Svetlanka [38]

Answer:

4.525% is the percentage by volume of oxygen in the gas mixture.

Explanation:

Total pressure of the mixture = p = 4.42 atm

Partial pressure of the oxygen = $p_1=0.20 atm$

Partial pressure of the helium = $p_2$

$p_1=p\times \chi_1$ (Dalton law of partial pressure)

$0.20 atm=4.42 atm\times \chi_1$

$\chi_1=\frac{0.20 atm}{4.42 atm}=0.04525$

$\chi_2=1-\chi_1=1-0.04525=0.95475$

$chi_1+chi_2=1$

$n_1=0.04525 mol,n_2=0.95475 mol$

According Avogadro law:

$Moles\propto Volume$ (At temperature and pressure)

Volume occupied by oxygen gas = $V_1$

Total moles of gases = n = 1 mol

Total Volume of the gases = V

$\frac{n_1}{V_1}=\frac{n}{V}$

$\frac{V_1}{V}=\frac{n_1}{n}=\frac{0.04525 mol}{1 mol}$

Percent by volume of oxygen in the gas mixture:

$\frac{V_1}{V}\times 100=\frac{0.04525 mol}{1 mol}\times 100=4.525\%$

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3 years ago

Covers 70 precent of earths surface

Anastaziya [24]

Answer:

<h2><u>W</u><u>ater</u> covers 70 percent of earth's surface.</h2>

5 0

2 years ago

grigory [225]

Answer:

The anser is C

Explanation:

This is because the fungi and bacteria are the decomposer, and their job is to decompose dead organism.

7 0

2 years ago

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Find the density of metal with a volume 4.0 cm and a mass of 8.0 grams.

olga_2 [115]

D=m/v

so,

d=8.0g/4.0cm

d=2

3 0

2 years ago