Hello!
The molarity of the HBr solution is 0,172 M.
Why?
The neutralization reaction between LiOH and HBr is the following:
HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)
To solve this exercise, we are going to apply the common titration equation:


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Answer:
A compound
Example:
Sugar contains carbon, hydrogen and oxygen. Water (H2O) has two hydrogen atoms (H2) and one oxygen atom (O). So both sugar and water are chemical compounds. Together they are a mix of chemical compounds.
Answer:
1. It depends what type of method you are using. if it is Height x Width x Length then it will not work for an irregular shape because it has extra pieces that would not be included.
2. The second method would work for both regular and irregular shapes because you would have to know or find out the volume of the regular shape to get the volume for the irregular shape.
3. It also depends on what you are doing, if you are doing a regular shape then use the first method, if it's an irregular shape then use the second method, if you do the maths correctly both should give you an accurate answer for what you want to achieve.
4. No, because the sugar would dissolve.
5. No, on this case the displacement method would not work because of the weight difference
Explanation:
All the answers for you!
Answer:
D. 5.6 g/cm^3
Explanation:
On the average seismic velocity increases with increase in depth due higher the pressure and more compaction
sand and shales in the Niger Delta Basin density–velocity relationship is
P = 0.31×V^0.25
A derivation of the original Gardner equation to calculate the average densities for sands and shales in wells.
ρ = α ×V^β
where
ρ = bulk density in g/cm3,
V = P-wave velocity,
α = 0.31 for V (m/s) and 0.23 for V(ft/s) and
β = 0.25.
Such that
ρ = 0.31 ×V^0.25
So the fastest seismic velocity will be in the densest material which is D. 5.6 g/cm3
Answer:
Explanation:
In general, an increase in pressure (decrease in volume) favors the net reaction that decreases the total number of moles of gases, and a decrease in pressure (increase in volume) favors the net reaction that increases the total number of moles of gases.
Δn= b - a
Δn= moles of gaseous products - moles of gaseous reactants
Therefore, <u>after the increase in volume</u>:
- If Δn= −1 ⇒ there are more moles of gaseous reactants than gaseous products. The equilibrium will be shifted towards the products, that is, from left to right, and K>Q.
- If Δn= 0 ⇒ there is the same amount of gaseous moles, both in products and reactants. The system is at equilibrium and K=Q.
- Δn= +1 ⇒ there are more moles of gaseous products than gaseous reactants. The equilibrium will be shifted towards the reactants, that is, from right to left, and K<Q.