Answer:
It is true that the sampling distribution of the proportions is approximately a normal distribution.
Explanation:
Solution
Given that:
N = 50
P= 0.8
Thus
p ^ =√p(1-p)/n
p ^=√0.8 (1-0.8)/50
p ^= 0.0566
Therefore,we conclude that the sampling distribution of the proportions is approximately a normal distribution.
Answer:
The change in specific internal energy is 3.5 kj.
Explanation:
Step1
Given:
Total change in energy is 15.5 kj.
Change in kinetic energy is –3.5 kj.
Change in potential energy is 0 kj.
Mass is 5.4 kg.
Step2
Calculation:
Change in internal energy is calculated as follows:


kj.
Step3
Specific internal energy is calculated as follows:


kj/kg.
Thus, the change in specific internal energy is 3.5 kj/kg.