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Tpy6a [65]
3 years ago
12

The First Telescopes created relied on the bending of the light to see objects in the night sky. This type of telescope is calle

d ?
A. Reflecting Telescope
B. Radio Telescope
C. Refracting Telescope
D. Space Telescope
Physics
1 answer:
Alenkinab [10]3 years ago
3 0
C. Refracting Telescope
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A small but bright light is at the bottom of a pool 2.2 m  deep. How wide is the circle of light that exits the surface of the
mixas84 [53]

Answer: 1.65m

Explanation:

Refractive index in terms of the depth of liquid is the ratio of the real depth to the apparent depth of the liquid i.e Refractive index =Real depth/apparent depth

Refractive index of water given = 1.33

Real depth is the measure of how deep is the liquid while apparent depth is the depth at the surface of the liquid.

Real depth = 2.2m

Apparent depth =?

Applying the formula above

Apparent depth =Real depth/refractive index

= 2.2/1.33

= 1.65m

Therefore, the circle of light that exits the surface of the water when that light shines in the middle of the night is 1.65m wide

5 0
2 years ago
Which point or points of view could be present in a business letter?
Studentka2010 [4]

Answer:

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Explanation:

6 0
3 years ago
Convert 30.0 degrees Celsius into Kelvin
frutty [35]

Answer:

303.15K

Explanation:

the formula for converting celsius into kelvin is adding 273.15 to the number

4 0
2 years ago
If a star is found directly above the sun on the h-r diagram, what can you conclude about its size?.
hammer [34]

Answer:

It is larger than the Sun.

Explanation:

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7 0
2 years ago
If half of the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration it can achieve o
Scilla [17]

Answer:

Maximum acceleration will be equal to 3.43m/sec^2

Explanation:

We have given coefficient of kinetic friction \mu _k=0.7

And coefficient of static friction \mu _s=1

Acceleration due to gravity g=9.8m/sec^2

When truck moves maximum force will be equal to F=\mu _kmg

It is given that half of the weight is supported by its drive wheels

So force required =\frac{\mu _kmg}{2}

From newtons law maximum acceleration will be equal to a=\frac{\frac{\mu _kmg}{2}}{m}=\frac{\mu _kg}{2}=\frac{0.7\times 9.8}{2}=3.43m/sec^2

8 0
3 years ago
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