What kind of change occurs with no new substance being formed apex?

1 answer:

5 0

<span>physical changes
Physical changes happen when something undergoes a transformation that does not alter their total inward arrangement. This appears differently in relation to the idea of compound change in which the creation of a substance changes or at least one substances consolidate or separate to frame a new one</span>

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How many molecules are there in 0.50 moles chlorine?

mariarad [96]

Answer:

molecules Cl- = 3.01 E23 molecules

Explanation:

molecules Cl- = 0.50 mol CL- * ( 6.02 E23 molecules/ mol ) = 3.01 E 23 molecules

3 0

3 years ago

Read 2 more answers

Write 0.00000009345 in Engineering Notation with 3 significant figures

melisa1 [442]

Answer:

$93.43\times 10^{-9}$

Explanation:

Scientific notation is the way of writing numbers which are either large or small. The number is written in the scientific notation when the number is between 1 and 10 and then multiplied by the power of 10. Engineering notation is the same version of the scientific notation but the number can be between 1 and 1000 and in this exponent of the ten is divisible by three.

For example, $1000^2$ is to be written as $10^6$ in engineering notation.

The given number:

0.00000009345 can be written as $93.425\times 10^{-9}$

Answer upto 4 significant digits = $93.43\times 10^{-9}$

6 0

2 years ago

A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o

Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

$\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }$

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

$\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}$