Answer: The molar solubility of in a solution that is buffered at ph 8.00 is 0.19 M
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as
We are given:
Solubility product of =
The equation for the ionization of the is given as:
1 mole of gives 1 mole of and 2 moles of
Given : pH = 8.00
Thus the molar solubility of in a solution that is buffered at ph 8.00 is 0.19 M
Answer:
The mass of water produced is 4.29 g.
Explanation:
Given;
reacting mass of ethane, C₂H₆ = 2.5 g
reacting mass of oxygen, O₂ = 5.0 g
The balanced combustion reaction is given as follows;
2C₂H₆ + 7O₂ ----------------> 4CO₂ + 6H₂O
Based on the balanced equation above;
requires
7.0 moles of oxygen -----------------------> 2.0 moles of ethane
requires
5.0 g of oxygen --------------------------> x gram of ethane
x = (2 x 5) / 7
x = 1.43 g
Ethane is in excess of 1.07g (2.5 g - 1.43g)
Now, determine the mass of water produced by 1.43 g of ethane;
requires
2.0 moles of ethane -----------------------> 6.0 moles of water
requires
1.43 g of ethane --------------------------> y gram of water
y = (6 x 1.43) / 2
y = 4.29 g
Therefore, the mass of water produced is 4.29 g.
a)CO is the main air pollutant (b) All pollutants are not wastes (c) Water is polluted by dissolved oxygen (d) Lichens are pollution indicatorsnation:
Answer:
false
Explanation:
as the particles move further apart their forces of attraction become qeak