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Murrr4er [49]
3 years ago
11

A crane dose 62500 joules of work to lift the boulder distance of 25 meters how much does the boulder way

Physics
2 answers:
Sunny_sXe [5.5K]3 years ago
5 0
Work = force x distance
62,500 joules = boulder's weight x 25 meters
Divide each side by 25 meters:
Boulder's weight = 62,500 joules / 25 meters = 2,500 newtons
That's about 562 pounds
vladimir2022 [97]3 years ago
4 0
Work is equal to force times distance.
-W=F*D or W=FD
Where force is measured in Newtons(N) and distance in meters(m). The unit for work is a newton-meter (aka joule(j))
All you have to do to find how much it weighs is do the opposite. So you would do 62500j/25m. That gives you 2500N, to check it you just multiply 2500N and 25m. Which gives you 62500j.
Hope this helped!

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Two wheels having the same radius and mass rotate at the same angular velocity. One wheel is made with spokes so nearly all the
Mazyrski [523]

Answer:

C. The wheel with spokes has about twice the KE.

Explanation:

Given that

Mass , radius and the angular speed for both the wheels are same.

radius = r

Mass = m

Angular speed = ω

The angular kinetic energy KE given as

KE=\dfrac{1}{2}I\omega ^2

I=Moment of inertia for wheels

Wheel made of spokes

I₁ = m r²

Wheel like a disk

I₂ = 0.5 m r²

Now by comparing kinetic energy

\dfrac{KE_1}{KE_2}=\dfrac{I_1}{I_2}

\dfrac{KE_1}{KE_2}=\dfrac{mr^2}{0.5mr^2}

\dfrac{KE_1}{KE_2}=2

KE₁= 2 KE₂

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A person throws a pumpkin at a horizontal speed of 4.0 — off a cliff. The pumpkin travels 9.5 m horizontally
emmainna [20.7K]

Complete Question

A person throws a pumpkin at a horizontal speed of   4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground. We can ignore air resistance.What is the pumpkin's vertical displacement during the throw? What is the pumpkin's vertical velocity when it hits the ground?

Answer:

The  pumpkin's vertical displacement  is  H = 27 .67 \ m

The  pumpkin's vertical velocity when it hits the ground is  v_v__{f}} = 23.298 \  m/s

Explanation:

From the question we are told that

   The  horizontal speed is  v_h  =  4 m/s

    The horizontal distance traveled is  d =  9.5 \ m

The horizontal distance traveled is mathematically represented as

           S =  v_h * t

Where t is the time taken

substituting values

          9.5 =  4 * t

   =>     t =  \frac{9.5}{4}

            t = 2.38 \ sec

Now the vertical displacement is mathematically represented as

        H  =  v_v t  +  \frac{1}{2} a_v t^2

now the vertical velocity before the throw is  zero

    So

          H =  0 +  \frac{1}{2} (9.8) * (2.375)^2

          H = 27 .67 \ m

Now the final vertical velocity  is mathematically represented as

          v_v__{f}} =  v_v + at

  substituting values

             v_v__{f}} =  0 + (9.8)* (2.375)

            v_v__{f}} = 23.298 \  m/s

7 0
3 years ago
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