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Murrr4er [49]
3 years ago
11

A crane dose 62500 joules of work to lift the boulder distance of 25 meters how much does the boulder way

Physics
2 answers:
Sunny_sXe [5.5K]3 years ago
5 0
Work = force x distance
62,500 joules = boulder's weight x 25 meters
Divide each side by 25 meters:
Boulder's weight = 62,500 joules / 25 meters = 2,500 newtons
That's about 562 pounds
vladimir2022 [97]3 years ago
4 0
Work is equal to force times distance.
-W=F*D or W=FD
Where force is measured in Newtons(N) and distance in meters(m). The unit for work is a newton-meter (aka joule(j))
All you have to do to find how much it weighs is do the opposite. So you would do 62500j/25m. That gives you 2500N, to check it you just multiply 2500N and 25m. Which gives you 62500j.
Hope this helped!

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6 0
3 years ago
Read 2 more answers
Your friend decides to generate electrical power by rotating a 100,000 turn coil of wire around an axis in the plane of the coil
MakcuM [25]

Answer:

a) I=35mA

b) P=1.73W

Explanation:

a) The max emf obtained in a rotating coil of N turns is given by:

emf_{max}=NBA\omega

where N is the number of turns in the coil, B is the magnitude of the magnetic field, A is the area and w is the angular velocity of the coil.

By calculating A and replacing in the formula (1G=10^{-4}T) we get:

A=\pi r^2 =\pi(0.23m)^2=0.16m^2

emf_{max}=(100000)(0.3*10^{-4}T)(0.166m^2)(140\frac{rev}{s})=69.72V

Finally, the peak current is given by:

I=\frac{emf}{R}=\frac{69.72V}{1400\Omega}=49.8mA

b)

we have that

I_{rms}=\frac{I}{\sqrt{2}}=\frac{0.0498A}{\sqrt{2}}=0.035A

P_{rms}=I^2{rms}R=(0.035A)^2(1400\Omega)=1.73W

hope this helps!!

6 0
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