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3 years ago

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Using benefit-cost ratio analysis, determine which one of the three mutually exclusive alternatives should be selected. Each alt

ernative has a 10-year useful life and 20% MARR 247 А в с First Cost $120 $340 $560 $760 Uniform Annual Beneft $40 $100 $140 $170 $0 $0 Salvage Value $40 $50 СА B Stop sharing app honorocos sharing your screen

1 answer:

anzhelika [568]3 years ago

8 0

Hamborger hamborger hamborger hamborger

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A 200-gr (7000 gr = 1 lb) bullet goes from rest to 3300 ft/s in 0.0011 s. Determine the magnitude of the impulse imparted to the

OlgaM077 [116]

Answer:

The force acting on the bullet $F = 84000 \frac{lb ft}{s^{2} }$

The value of impulse on the bullet in the given time interval P = 92.4 $\frac{lb ft}{sec}$

Explanation:

Mass of the bullet ( m ) = 200 gr = 0.028 lb

Initial velocity ( U ) = 0

Final Velocity ( V ) = 3300 $\frac{ft}{sec}$

Force acting on the bullet $F = \frac{m ( V - U )}{t}$

⇒ $F = \frac{ 0.028 ( 3300 - 0 )}{0.0011}$

⇒ $F = 84000 \frac{lb ft}{s^{2} }$

This is the force acting on the bullet.

Magnitude of the impulse imparted on the bullet $P = F dt$ -------- (1)

Put the value of F & dt in above equation we get,

P = 84000 × 0.0011

P = 92.4 $\frac{lb ft}{sec}$

This is the value of impulse on the bullet in the given time interval.

3 0

3 years ago

Air is to be heated steadily by an 8-kW electric resistance heater as it flows through an insulated duct. If the air enters at 5

Furkat [3]

To solve this problem it is necessary to apply the concepts related to the heat exchange of a body.

By definition heat exchange in terms of mass flow can be expressed as

$W = \dot{m}c_p \Delta T$

Where

$C_p =$ Specific heat

$\dot{m}$ = Mass flow rate

$\Delta T$ = Change in Temperature

Our values are given as

$C_p = 1.005kJ/kgK \rightarrow$ Specific heat of air

$T_1 = 50\°C$

$\dot{m} = 2kg/s$

$W = 8kW$

From our equation we have that

$W = \dot{m}c_p \Delta T$

$W = \dot{m}c_p (T_2-T_1)$

Rearrange to find $T_2$

$T_2 = \frac{W}{\dot{m}c_p}+T_1$

Replacing

$T_2 = \frac{8}{2*1.005}+(50+273)$

$T_2 = 326.98K \approx 53.98\°C$

Therefore the exit temperature of air is 53.98°C

6 0

3 years ago

In fully developed laminar flow in a circular pipe the velocity at R/2 (mid-way between the wall surface and the centerline) is

Butoxors [25]

Answer:

$u_{max} = 17.334\,\frac{m}{s}$

Explanation:

Let consider that velocity profile inside the circular pipe is:

$u(r) = 2\cdot U_{avg} \cdot \left(1 - \frac{r^{2}}{R^{2}} \right)$

The average speed at $r = \frac{1}{2} \cdot R$ is:

$U_{avg} = \frac{13\,\frac{m}{s} }{2\cdot \left(1-\frac{1}{4} \right)}$

$U_{avg} = 8.667\,\frac{m}{s}$

The velocity at the center of the pipe is:

$u_{max} = 2\cdot U_{avg}$

$u_{max} = 17.334\,\frac{m}{s}$

6 0

3 years ago

Read 2 more answers

A motor vehicle has a mass of 1200kg and the road wheels have a radius of 360mm. The engine rotating parts have a moment of iner

mihalych1998 [28]

Answer:

manda a senha do brainly bloquearam os amigos e você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo uma academia de lima e você vai ver o meu perfil completo a minha amiga Jeciane estamos completo a minha amiga Jeciane estamos fazendo uma academia de lima e você vai ver o meu perfil você vai ver o meu perfil você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo

Explanation:

Marcar como melhor porfavo

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3 years ago

500 flights land each day at San Jose’s airport. Assume that each flight has a 5% chance of being late, independently of whether

BARSIC [14]

Answer:

a.0.0199

b.0.1765

c.0.0785

d.0.1268

e.Yes

Explanation:

It is given that X follows a Binomial distribution with (n= 500, p = 0.05)

The probabilities are computed using the EXCEL .

a) The required probability here is:

P(X less of equal to 15)

= binom.dist(15,500,0.05,TRUE)

=0.0199

Therefore the probability is 0.0199 .

b) The required probability here is:

P(X greater or equal to 30) = 1 - P(X less or equal to 29)

=1 - binom.dist(29,500,0.05,TRUE)

=0.1765

Therefore the probability is 0.1765

c) P(X = 26 )

= binom.dist(26,500,0.05,FALSE)

=0.0785

Therefore the probability is 0.0785

d) The required probability here is computed as:

P(10 less or equal to X less or equal to 20 ) = P(X less or equal to 19) - P(X less or equal to 10)

= binom.dist(19,500,0.05,TRUE) - binom.dist(10,500,0.05,TRUE)

=0.1268

Therefore the probability 0.1268

e) Yes . Therefore the probability because that is the assumption used to apply binomial distribution .

6 0

3 years ago