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user100 [1]
3 years ago
13

A typical coffee mug holds about 355,000 microliters of liquid. How many kiloliters of liquid does this mug hold expressed in st

andard Scientific notation?
Chemistry
1 answer:
skad [1K]3 years ago
3 0

Answer:

3.55\times 10^{-4}\ kL

Explanation:

Given that,

A typical coffee mug holds about 355,000 microliters of liquid.

1\ \mu L=10^{-6}\ L

Also, 1 L = 0.001 kL

10^{-6}\ L=0.001\times 10^{-6}\ kL\\\\=10^{-9}\ kL

So, a typical coffee mug holds about 355000 \times 10^{-9}\ kL or 0.000355\ kL of liquid.

We need to convert it into Scientific notation.

We will shift 4 zeros to right. As a result,

V=3.55\times 10^{-4}\ kL

So, the mug will hold 3.55\times 10^{-4}\ kL of liquid.

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Answer:
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Explanation:
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Is this the correct procedure for cleaning volumetric glassware prior to making a measurement: first, rinse with tap water. Seco
Bogdan [553]

The steps to be followed while cleaning volumetric glassware are:

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2. The glassware is then soaked overnight in warm soap solution.

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4. After scrubbing, the glassware is rinsed thoroughly with tap water in order to make sure there are no traces of soap solution.

5. The glassware is then rinsed with de-ionized water and finally with the solution that would be used for the volumetric measurement.

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KBr + AgNO3 → AgBr + KNO3<br><br><br> Which two chemicals are products in the chemical reaction?
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3 years ago
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0144 0.0144 M solution. The pH of the resulting solution i
alexdok [17]

Answer:

The value of dissociation constant of the monoprotic acid is 1.099\times 10^{-3}.

Explanation:

The pH of the solution = 2.46

pH=-\log[H^+]

2.46=-\log[H^+]

[H^+]=0.003467 M

HA\rightleftharpoons H^++A^-

Initially

0.0144         0      0

At equilibrium

(0.0144-x)       x       x

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K_a=\frac{[A^-][H^+]}{[HA]}

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K_a=\frac{0.003467 \times 0.003467 }{(0.0144-0.003467 )}

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The value of dissociation constant of the monoprotic acid is 1.099\times 10^{-3}.

3 0
3 years ago
Copper is formed when aluminum reacts with copper (II) sulfate in a single-replacement reaction. How many moles of copper can be
serg [7]

Answer:

The answer to your question is the limiting reactant is CuSO₄ and 0.975 moles of Cu were obtained

Explanation:

moles of Copper = ?

mass of Aluminum = 29 g

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Limiting reactant = ?

Balanced Chemical reaction

                  3 CuSO₄   +  2 Al   ⇒   3 Cu   +  Al₂(SO₄)₃

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Al = 27 g

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                156 g                   -----------------  x

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                         x = (0.975 x 3)/3

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