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Mashutka [201]
3 years ago
5

Please explain how to find each answer solution.

Chemistry
1 answer:
svp [43]3 years ago
7 0

Explanation:

1) Based on the octet rule, iodine form an <u>I</u>⁻ ion.

Therefore,

Option E is correct ✔

2) The electronic configuration of the sulfide ion (S²⁻) is :

₁₆S = 1s² 2s² 2p⁶ 3s² 3p⁴ or [Ne] 3s² 3p⁴

₁₈S²⁻ = 1s² 2s² 2p⁶ 3s² 3p⁶ or [Ne] 3s² 3p⁶

Therefore,

Option E is correct ✔

3) valence shell electron of

Halogens = 7

Alkali metal = 1

Alkaline earth metal = 2

Therefore,

Option D is correct ✔

4) Group 2 element lose two electron in order to achieve Noble gas configuration.

And here Group 2 element is Sr

Therefore,

Option B is correct ✔

5) Group 13 element lose three electron in order to achieve Noble gas configuration.

And here Group 13 element is Al

Therefore,

Option B is correct ✔

6) For a given arrangements of ions, the lattice energy increases as ionic radius <u>decreases</u> and as ionic charge <u>increases</u>.

Therefore,

Option A is correct ✔

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Answer:

CHORUS 1:

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CHORUS 2:

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Slow moves. Long time. Slow moves. Long time

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Explanation:

4 0
3 years ago
Read 2 more answers
You need to prepare at 2.0 mL sample of a diluted drug for injection. The total amount of the drug to be injected in this 2.0 mL
pav-90 [236]

Answer:

a) The concentration of drug in the bottle is 9.8 mg/ml

b) 0.15 ml drug solution + 1.85 ml saline.

c) 4.9 × 10⁻⁵ mol/l

Explanation:

Hi there!

a) The concentration of the drug in the bottle is 294 mg/ 30.0 ml = 9.8 mg/ml

b) The drug has to be administrated at a dose of 0.0210 mg/ kg body mass. Then, the total mass of drug that there should be in the injection for a person of 70 kg will be:

0.0210 mg/kg-body mass * 70 kg = 1.47 mg drug.

The volume of solution that contains that mass of drug can be calculated using the value of the concentration calculated in a)

If 9.8 mg of the drug is contained in 1 ml of solution, then 1.47 mg drug will be present in (1.47 mg * 1 ml/ 9.8 mg) 0.15 ml.

To prepare the injection, you should take 0.15 ml of the concentrated drug solution and (2.0 ml - 0.15 ml) 1.85 ml saline

c) In the injection there is a concentration of (1.47 mg / 2.0 ml) 0.735 mg/ml.

Let´s convert it to molarity:

0.735 mg/ml * 1000 ml/l * 0.001 g/mg* 1 mol/ 15000 g = 4.9 × 10⁻⁵ mol/l

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