How was the arched formed

Calculate the molecular formula of a compound with the empirical formula C5H11 and a molar mass of 142.32 grams/mole

MA_775_DIABLO [31]

Relative formula mass C₅H₁₁ = 71

Now divide the molar mass by the RFM = 142.32 / 71 = 2

Now C₍₅ₓ₂₎H₍₁₁ₓ₂) = C₁₀H₂₂

Hope that helps

6 0

3 years ago

A second-order reaction has a rate law: rate = k[a]2, where k = 0.150 m−1s−1. If the initial concentration of a is 0.250 m, what

Cerrena [4.2K]

Rate law for the given 2nd order reaction is:

Rate = k[a]2

Given data:

rate constant k = 0.150 m-1s-1

initial concentration, [a] = 0.250 M

reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s

To determine:

Concentration at time t = 300 s i.e. $[a]_{t}$

Calculations:

The second order rate equation is:

$1/[a]_{t} = kt +1/[a]$

substituting for k,t and [a] we get:

1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M

1/[a]t = 49 M-1

[a]t = 1/49 M-1 = 0.0204 M

Hence the concentration of 'a' after t = 5min is 0.020 M

7 0

3 years ago

how would you write equation to show how buffers H2CO3 and NaHCO3 behave when (a) HCl is added and (b) NaOH is added.

Vlad1618 [11]

<span>H2CO3 <---> H+ + HCO3-
NaHCO3 <---> Na+ + HCO3-

When acid is added in the buffer, the excess H+ of that acid reacts with HCO3- to form H2CO3, and due to this NaHCO3 dissociates into HCO3- to attain the equilibrium. and hence there is no net effect of H+ due to pH remain almost constant. when a base is added to the buffer, the OH- ion of base react eith H+ ion present in buffer, then to attain equilibrium of H+ ion, the H2CO3 dissociates to produce H+ ion, but now there is the excess of HCO3- due to which Na+ ion react with them to attain equilibrium of HCO3-. hence there is again no net change in H+ ion due to which pH remain constant.....</span>

8 0

3 years ago

A mixture of H2 and water vapor is present in a closed vessel at 20°C. The total pressure of the system is 755.0 mmHg.

sukhopar [10]

Answer:

737.5mmHg

Explanation:

7 0

3 years ago

In the citric acid cycle (also known as the Krebs cycle), acetyl CoA is completely oxidized. From the following compounds involv

REY [17]

Answer:

We place ( O₂, CO₂, coenzyme A and acetyl CoA) into bin [not input or output];

We place (ADP, NAD⁺, Glucose) into [ Net Input] bin.;

And (ATP, NADH and Pyruvate) intothe [Net Output] bin.

Explanation:

Citric Acid Cycle is also known as Tricarboxylic Acid Cycle, Krebs Cycle and Szent-Györgyi-Krebs cycle.

It is a series of enzyme-catalyzed chemical reactions, which of central importance in all living cells that use oxygen as part of cellular respiration.

Here are few things to know about the CAC:

• The Krebs cycle uses the products of Glycolysis to produce 2 ATP molecules for each molecule of Glucose.

• Oxygen is required.

• The Krebs Cycle occurs in cellular power plant — Mitochondria of the cell.

• Each glucose molecule nets 2 pyruvic acids. The Krebs Cycle breaksdown 1 pyruvic acid one at å time.

• CAC begins and ends with Oxaloacetic Acid - a 4 carbon molecule.

• It is an 8 step cycle that begins when the Acetyl CoA that is a product of Glycolysis is 'picked up' by Oxalacetic Acid.

• Lipids, Proteins and Carbohydrates can all be metabolized in the Krebs Cycle.

• The NADH and FADH2 that are high energy co- enzymes (helper molecules) are by-products of the Krebs cycle and continue on to fuel the Electron Transport Chain.

The clues above helps us to know where to drag the compounds into;

We place these into bin of [Net Input]: ADP, NAD⁺, Glucose

We place these into the bin of [Net Output]: ATP, NADH and Pyruvate,

We place the following into [not input or output] bin: O₂, CO₂, coenzyme A and acetyl CoA

3 0

2 years ago

How was the arched formed ​

How was the arched formed