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Svetlanka [38]
3 years ago
5

QUESTION 11

Chemistry
1 answer:
Iteru [2.4K]3 years ago
6 0
I actually don’t know but good question
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What strategies did you use when you played the balancing chemical equations game? Which atoms were the easiest to start examini
Yakvenalex [24]

<u>Answer:</u>

<em>Latest take an example to understand how </em><em>balancing of chemical reaction</em><em> is done that is assuming the reaction between iron as well as </em><em>oxygen which reacts to form rust.</em>

<u>Explanation:</u>

For this we would simply right the reactant and product that is expected. Then we would see the number of molecules of each element present on either side.

If in the reaction the element’s molecules are the same on both sides then the reaction would be correct and if not then we have to apply trial and error method to balance the equation such that the number of molecules of each element is equal on both sides of the reaction.

3 0
3 years ago
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Why doesn't the stomach acid just digest right through the wall of the stomach? Select one: a.Neutralizers are imbedded in the s
Lostsunrise [7]

Answer:

d

Explanation:

5 0
3 years ago
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How many electrons are in an atom with the electron<br> configuration of 1s 2s 2p 3s!?
Viefleur [7K]

Answer:

11

Explanation:

electronic configuration = 1s^2, 2s^2, 2p^6, 3s^1

therefore total electrons = 2+2+6+1 = 11

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>youu</em><em> </em>。◕‿◕。

6 0
2 years ago
How many milliliters of 0.500 M NaOH should be added to 10.0 g of tris hydrochloride (FM 121.135) to give a pH of 7.60 in a fina
liubo4ka [24]

Answer:

41.64mL of NaOH 0.500M must be added to obtain the desire pH

Explanation:

It is possible to find pH of a buffer by using H-H equation, thus:

pH = pka + log [A⁻] / [HA]

<em>Where [HA] is concentration of the weak acid TRIS-HCl and [A⁻] is concentration of its conjugate acid.</em>

Replacing in H-H equation:

7.60 = 8.072 + log [A⁻] / [HA]

0.3373 =  [A⁻] / [HA] <em>(1)</em>

10.0g of TRIS-HCl (Molar mass: 121.135g/mol) are:

10.0g ₓ (1mol / 121.135g) = 0.08255 moles of acid. That means moles of both the acid and conjugate base are:

[A⁻] + [HA] = 0.08255 <em>(2)</em>

Replacing (1) in (2):

0.3373 =  0.08255 - [HA] / [HA]

0.3373[HA] =  0.08255 - [HA]

1.3373[HA] = 0.08255

<em>[HA] = 0.06173 moles</em>

Thus:

[A⁻]  = 0.08255 - 0.06173 = 0.02082 moles [A⁻]

The moles of A⁻ comes from the reaction of the weak acid with NaOH, that is:

HA + NaOH → A⁻ + H₂O + K⁺

Thus, <em>you need to add 0.02082 moles of NaOH to produce 0.02082 moles of A⁻. </em>As NaOH solution is 0.500M:

0.02082 moles NaOH ₓ (1L / 0.500mol) = 0.04164L of NaOH 0.500M =

<h3>41.64mL of NaOH 0.500M must be added to obtain the desire pH</h3>

3 0
3 years ago
Investigate and explain that when a force is applied to an object but it does not move, it is because another opposing force is
N76 [4]

Answer:

4. Force 1 Force 2 Comparison of Forces

Friction Gravity Force 1 is equal to Force 2

Explanation:

5 0
3 years ago
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