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Orlov [11]
3 years ago
9

HELP!!

Chemistry
1 answer:
NARA [144]3 years ago
8 0
A dichotomous key is an important scientific tool, used to identify different organisms, based the organism's observable traits. Dichotomous keys consist of a series of statements with two choices in each step that will lead users to the correct identification.
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I need help with these 4
storchak [24]

Rift Valley Examples

  • East African
  • Rhine Rift Valley (Germany)
  • Baikal Rift Valley (Russia)

Rift Valley Facts/Characteristics

  • Bordered by fault zones and separating land masses
  • A portion of land that drops, forming a valley.
  • Formed as tectonic plates move.

Fossils - Examples

  • Bones
  • Shells
  • Exoskeletons
  • Stone imprints of animals.

Non Examples of Fossils

  • Stones
  • rocks
  • Some bones (If they are fossils they will be a lot heavier than other bones.

Hope this helps.

5 0
3 years ago
The end point of a titration was reached after 22 ml of 0.050 m disodium edta titrant was dispensed into a solution containing t
ale4655 [162]
The moles  of disodium edta  used is  calculated  using  the  below  formula


moles =molarity  x  volume in  liters

molarity=0.050m
volume  in  liters = 22/1000=0.022 L

moles  is  therefore=  0.022 x0.050  =1.1  x10^-3  moles  of  disodium  edta


4 0
3 years ago
Read 2 more answers
The solubility of KCl is 3.7 M at 20 °C. Two beakers each contain 100. mL of saturated KCl solution: 100. mL of 4.0 M HCl is add
JulijaS [17]

Answer:

a)The Ksp was found to be equal to 13.69

Explanation:

Terminology

Qsp of a dissolving ionic solid — is the solubility product of the concentration of ions in solution.

Ksp however, is the solubility product of the concentration of ions in solution at EQUILIBRIUM with the dissolving ionic solid.

Note that if Qsp > Ksp , the solid at a certain temperature, will precipitate and form solid. That means the equilibrium will shift to the left in order to attain or reach equilibrium (Ksp).

Step-by-step solution:

To solve this: 

#./ Substitute the molar solubility of KCl as given into the ion-product equation to find the Ksp of KCl.

#./ Find the total concentration of ionic chloride in each beaker after the addition of HCl. We pay attention to the amount moles present at the beginning and the moles added.

#./ Find the Qsp value to to know if Ksp is exceeded. If Qsp < Ksp, nothing will precipitate.

a) The equation of solubility equilibrium for KCL is thus;

KCL_(s) ---> K+(aq) + Cl- (aq)

The solubility of KCl given is 3.7 M.

Ksp= [K+][Cl-] = (3.7)(3.7) =13.69

The Ksp was found to be equal to 14.

In pure water KCl

Ksp =13.69 KCl =[K+][Cl-]

Let x= molar solubility [K+],/[Cl-] :. × , x

Ksp =13.69 = [K+][Cl-] = (x)(x) = x²

x= √ 13.69 = 3.7 M moles of KCl requires to make 100mL saturated solutio

37M moles/L

The Ksp was found to be equal to 14.

4.0 M HCl = KCl =[K+][Cl-]

Let y= molar solubility :. y, y+4

Ksp =13.69= [K+][Cl-] = (y)(y*+4)

* - rule of thumb

Ksp =13.69= [K+][Cl-] = (y)(y*+4)= y(4)

13.69=4y:. y= 3.42 moles/100mL

y= 34.2moles/L

8 M HCl = KCl =[K+][Cl-]

Let b= molar solubility :. B, b+8

Ksp =13.69= [K+][Cl-] = (b)(b*+8)

* - rule of thumb

Ksp =13.69= [K+][Cl-] = (b)(b*+8)= b(8)

13.69=8b:. b= 1.71 moles/100mL

17.1 moles/L

Therefore in a solution with a common ion, the solubility of the compound reduces dramatically.

8 0
2 years ago
Read 2 more answers
Write the equation for the neutralization reaction in which barium chloride is the salt formed. Show the reaction in which the f
frutty [35]

Answer:

2 HCl + Ba(OH)₂ ⇒ BaCl₂ + 2 H₂O

Explanation:

In a complete neutralization reaction, an acid reacts with a base to form neutral salt and water. To form barium chloride, hydrochloric acid (acid) reacts with barium hydroxide  (base). The balanced chemical equation is:

2 HCl + Ba(OH)₂ ⇒ BaCl₂ + 2 H₂O

8 0
2 years ago
Jamal is working with three ionic compounds: sodium chloride, calcium sulfide, and barium oxide. His teacher asks him which are
Lubov Fominskaja [6]

Answer:

option A is correct  ( sodium, calcium and barium)

Explanation:

Given compounds:

Sodium chloride , calcium sulfide, barium oxide

We know that metals form positive ions. In order to solve the problem we must identify the metals from given compounds.

Na⁺Cl⁻

Ca²⁺S²⁻

Ba²⁺O²⁻

We can see that sodium, calcium and barium contain positive charges.

Thus option A is correct.

Because sodium have one valance electron. When it combine with chlorine sodium lose its one electron to complete the octet and chlorine accept it to complete its octet. Thus sodium form positive ion and chlorine form negative ion.

Similarly barium and calcium are present in group 2. Both have two valance electron. When they lose them cation are formed.

Other option are incorrect because,

Option B have sulfur and oxygen which are anion.

Option C have chlorine which is also anion

Option D have chlorine, sulfur and oxygen that are anions.

4 0
3 years ago
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