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Klio2033 [76]
3 years ago
5

Could someone please help?

Physics
2 answers:
ira [324]3 years ago
7 0
The correct answer is B Saturn’s outer rings.
KatRina [158]3 years ago
4 0
Answer: Outer rings


Explanation:




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" An object<span> at rest stays at rest and </span>an object <span>in motion stays in motion with the same speed and in the same direction </span>unless acted upon<span> by an </span>unbalanced force<span>."- Newtons first Law of Motion

Also, velocity is the speed of something in a given direction (So, 50mph North is an example of velocity)</span>
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C. infrared waves

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After the box comes to rest at position x1, a person starts pushing the box, giving it a speed v1. When the box reaches position
SVETLANKA909090 [29]

Answer:

w_p = \frac{1}{2}mv_1^2+\frac{1mv_0^2}{2x_1}(x_1-x_2)

Explanation:

First, the box goes from position x=0 to x=x1, so, the work made by the friction is calculated as:

-F_f(x_1) = \frac{1}{2}mV^2 -\frac{1}{2}mv_0^2

where F_f is the force of friction, x_1 the displacement, m the mass, V is the speed in rest and v_0 the initial speed.

V is equal to zero, so:

F_f(x_1)=\frac{1}{2}mv_0^2

it means that the force of friction F_f is equal to:

F_f = \frac{1mv_0^2}{2x_1}

On the other hand, when the box goes from position x=x1 to x=x2, the work-energy theorem said that:

-F_f(x_1-x_2)+w_p = \frac{1}{2}mv_1^2-\frac{1}{2}mV^2

Where w_p is the work done by the person.

Then, solving for w_p:

-F_f(x_1-x_2)+w_p = \frac{1}{2}mv_1^2

w_p = \frac{1}{2}mv_1^2+F_f(x_1-x_2)

Finally, replacing F_f by \frac{1mv_0^2}{2x_1}, we get:

w_p = \frac{1}{2}mv_1^2+\frac{1mv_0^2}{2x_1}(x_1-x_2)

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4 years ago
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