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Leto [7]
3 years ago
13

(I will give a brainliest) State the relationship between phase changes and temperature

Chemistry
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

The relationship is the "<em>variation</em><em> </em><em>of</em><em> </em><em>vapour</em><em> </em><em>pressure</em><em> </em><em>with</em><em> </em><em>temperature</em><em>"</em><em> </em>or <em>"</em><em> </em><em>the</em><em> </em><em>effect</em><em> </em><em>of</em><em> </em><em>vapour</em><em> </em><em>pressure</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>melting</em><em> </em><em>and</em><em> </em><em>boiling</em><em> </em><em>points</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>phase</em><em>"</em>

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Answer:

3.01 x 103 J

Explanation:

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3 0
3 years ago
A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi
Mkey [24]

The initial volume is 116.65 mL

<u>Explanation:</u>

<u />

Given:

Temperature, T₁ = 22°C

T₂ = 86°C

Volume, V₂ = 456 m

V₁ = ?

According to Charle's law:

\frac{V_1}{T_1} = \frac{V_2}{T_2}

Substituting the values:

\frac{V_1}{22} =\frac{456}{86} \\\\V_1 = \frac{456 X 22}{86} \\\\V_1 = 116.65 mL

Therefore, the initial volume is 116.65 mL

3 0
3 years ago
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Pani-rosa [81]
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Explanation:

8 0
2 years ago
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Answer:

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