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Elena-2011 [213]
3 years ago
12

Identify the products that are in equilibrium with NH3 and H2O.Identify the products that are in equilibrium with and .NH2−and H

3O+NH2−, H+, and H2ONH3and H2ONH4+and −OHNH3, H+, and −OH
Chemistry
2 answers:
kkurt [141]3 years ago
3 0

Answer:

NH4+and −OH

Explanation:

The reaction of the ammonia and water is as follows:

NH₃ + H₂O  =  NH₄⁺  + OH⁻

The reaction is an equilibrium reaction. The NH₃ is a Lewis base. It accepts a proton. The  H₂O is a Lewis acid, it donates a proton to the NH₃

Thus, the reaction above is correct.

SVEN [57.7K]3 years ago
3 0

Answer:

NH₄⁺ and OH⁻

Explanation:

The reaction of NH₃ and H₂O can be as follows:

NH₃ + H₂O --------> NH₂⁻ + H₃O⁺

NH₃ + H₂O --------> NH₄⁺ + OH⁻

Now which of these 2 equations is the correct one?

Well, we need to analyze the compouds per separate.

The case of NH₃, Nitrogen has 5 electrons, and we can see that 3 of them are bonding with the hydrogens. So it has 2 lone pairs available for any reaction. Same thing happen with the water. it has 4 lone pairs available for any reactions.

However, the lone pair of the nitrogen are more available because it have less electronegativy than oxygen, therefore, the NH₃ will act as a base in the reaction, while the water will act as acid.

If this s the case, NH3 is a base so it will donate an atom of hydrogen to the water, and the water as acid, will accept that. (Acid base theory by Bronsted - Lowry), therefore the correct reaction will be:

<h2>NH₃ + H₂O --------> NH₄⁺ + OH⁻</h2>
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3) In the reaction below, how many grams of carbon dioxide are produced when iron III
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<h3>Answer:</h3>

132.03 g

<h3>Explanation:</h3>

<u>We are given;</u>

  • The equation for the reaction as;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

  • Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
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We are required to calculate the mass of CO₂ that will produced.

<h3>Step 1: Calculate the number of moles of CO</h3>

Moles = Mass ÷ Molar mass

Molar mass of CO = 28.01 g/mol

Therefore;

Moles of CO = 84 g ÷ 28.01 g/mol

                     = 2.9989 moles

                    = 3.0 moles

<h3>Step 2: Calculate the number of moles of CO₂</h3>
  • From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
  • Therefore; the mole ratio of CO to CO₂ is 1 : 1
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Moles of CO₂ = 3.0 Moles

But; mass = Moles × molar mass

Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol

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Hence, the mass of CO₂ produced from the reaction is 132.03 g

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The differential rate expression for the rate of change in the concentration of B with time is
-rB = dCB/dt = kCB^n
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n is the order of the reaction
This is assuming that the rate is only affected by the concentration of B and the order of the reaction is in the nth order.
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