Question

Identify the products that are in equilibrium with NH3 and H2O.Identify the products that are in equilibrium with and .NH2−and H3O+NH2−, H+, and H2ONH3and H2ONH4+and −OHNH3, H+, and −OH

Answer 1

Answer:

NH4+and −OH

Explanation:

The reaction of the ammonia and water is as follows:

NH₃ + H₂O  =  NH₄⁺  + OH⁻

The reaction is an equilibrium reaction. The NH₃ is a Lewis base. It accepts a proton. The  H₂O is a Lewis acid, it donates a proton to the NH₃

Thus, the reaction above is correct.

Answer 2

Answer:

NH₄⁺ and OH⁻

Explanation:

The reaction of NH₃ and H₂O can be as follows:

NH₃ + H₂O --------> NH₂⁻ + H₃O⁺

NH₃ + H₂O --------> NH₄⁺ + OH⁻

Now which of these 2 equations is the correct one?

Well, we need to analyze the compouds per separate.

The case of NH₃, Nitrogen has 5 electrons, and we can see that 3 of them are bonding with the hydrogens. So it has 2 lone pairs available for any reaction. Same thing happen with the water. it has 4 lone pairs available for any reactions.

However, the lone pair of the nitrogen are more available because it have less electronegativy than oxygen, therefore, the NH₃ will act as a base in the reaction, while the water will act as acid.

If this s the case, NH3 is a base so it will donate an atom of hydrogen to the water, and the water as acid, will accept that. (Acid base theory by Bronsted - Lowry), therefore the correct reaction will be:

NH₃ + H₂O --------> NH₄⁺ + OH⁻