What is this equation?

Why don’t these gases tend to form chemical bonds?

erik [133]

If you’re talking about noble gases, the answer would be A. Since noble gases already have 8 electrons, they don’t tend to form chemical bonds. And elements need just 8 electrons on there shells to be stable.

6 0

3 years ago

Formal units are formed by?

cupoosta [38]

Answer:

However, when formal units are used to measure length, the measurement can usually be read from a scale on a ruler or tape, which shows units of a particular size. Unit iteration involves knowledge of repeatedly placing identical tightly packing units so that there are no overlaps or gaps.

Explanation:

4 0

2 years ago

Please help<br><br>Differentiate between the three systems of rearing pigs.

natulia [17]

this is ur answer

plzzz mark me as brainliest

5 0

3 years ago

Jenny measures the temperature inside a cave to be 10°C. The temperature outside the cave is about 30°C warmer. How does the kin

ExtremeBDS [4]

<h2>Answer:</h2>

<em><u>The kinetic energy of the air molecules in the cave is less than the kinetic energy of molecules outside the cave.</u></em>

<h3>Explanation:</h3>

The kinetic energy of any molecule is directly proportional to the temperature of the gas.

Temperature of a gas is the heat energy provided to the molecules. As the temperature energy increase the molecules of the gas will move fastly and collide with each other.

So we can know the kinetic energy of molecules in the gas by measuring its temperature.

Hence the temperature of the cave is less than outside, so the kinetic energy will also be low.

8 0

3 years ago

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If a single gold atom has a diameter of 2.9×x10−8 cm, how many atoms thick was rutherford's foil

ale4655 [162]

27,586

<h3>Further explanation</h3>

<u>Given:</u>

A single gold atom has a diameter of $\boxed{ \ 2.9 \times 10^{-8} \ cm. \ }$

From a reference, the Rutherford gold foil used in his scattering experiment had a thickness of approximately $\boxed{ \ 8 \times 10^{-3} \ mm. \ }$

<u>Question:</u>

How many atoms thick were Rutherford's foil?

<u>The Process:</u>

Convert thickness from mm to cm.

$\boxed{ \ 8 \times 10^{-3} \ mm = 8 \times 10^{-3} \times 10{-1} \ cm \ } \rightarrow \boxed{ \ 8 \times 10^{-4} \ cm \}$

The number of atoms is calculated from gold foil thickness divided by the atomic diameter.

$\boxed{ \ = \frac{8 \times 10^{-4} \ cm}{2.9 \times 10^{-8} \ cm} \ }$

$\boxed{ \ =2.7586 \times 10^4 \ atoms \ }$

Therefore, we get an atomic thickness of 27,586 atoms.

<u>Notes:</u>

In 1909-1910, Ernest Rutherford with two of his assistants, namely Hans Geiger and Ernest Marsden, conducted a series of experiments to find out more about the arrangement of atoms. They fired at a very thin gold plate with high-energy alpha particles.
One of their observations is that a small portion of alpha particles are reflected. This greatly surprised Rutherford. The reflected alpha particle must have hit something very dense in the atom. This fact is incompatible with the atomic model proposed by J.J. Thomson where the atoms are described as homogeneous in all parts with electrons and protons evenly distributed.
In 1911, Rutherford was able to explain the scattering of alpha rays by proposing ideas about atomic nuclei. According to him, most of the mass and positive charge of atoms are concentrated at the center of the atom, hereinafter referred to as the nucleus.

<h3>Learn more</h3>

The energy density of the stored energy brainly.com/question/9617400
The theoretical density of platinum which has the FCC crystal structure. brainly.com/question/5048216
Compound microscope brainly.com/question/4000241

Keywords: if a single gold atom, has a diameter of 2.9 x 10⁻⁸ cm, how many, atoms thick, Rutherford's foil, his scattering experiment

7 0

3 years ago

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