All categories

3 years ago

Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kJ of heat. The bomb

Chemistry

1 answer:

I am Lyosha [343]3 years ago

4 0

Answer:

i cant understand what you wrote

Explanation:

it's a blank screen

You might be interested in

Define energy conservation.

Reil [10]

Energy conservation is the effort made to reduce the consumption of energy by using less of an energy service. This can be achieved either by using energy more efficiently or by reducing the amount of service used. Energy conservation is a part of the concept of Eco-sufficiency

5 0

3 years ago

Use the law of conservation of mass to answer the questions. Consider a hypothetical reaction in which A and B are reactants and

shutvik [7]

Answer:

26 grams of D will be produced.

Explanation:

The reaction is given by:

A + B -----> C + D

Mass of A reacted = 21 g

Mass of B reacted = 22 g

Mass of C formed = 17 g

Mass of D formed = m =?

According to law of conservation of mass, the total mass of the reactants used is equal to the total mass of the product formed.

Then:

mass of A reacted + mass of B reacted = mass of C formed + mass of D formed

21 + 22 = 17 + m

m = 26 g

5 0

4 years ago

Consider four elements from Group 17: fluorine in the second period, chlorine in the third period, bromine in the fourth period,

nika2105 [10]

Answer:

A. Fluorine

Explanation:

I got it right on Plato.

6 0

3 years ago

solution was prepared by dissolving 43.0 g of KCl in 225 g of water. Part A Calculate the mole fraction of the ionic species KCl

notka56 [123]

Answer: The mole fraction of KCl in the solution is 0.044

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For KCl:

Given mass of KCl = 43.0 g

Molar mass of KCl = 74.5 g/mol

Putting values in equation 1, we get:

$\text{Moles of KCl}=\frac{43g}{74.5g/mol}=0.58mol$

For water:

Given mass of water = 225 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{225g}{18g/mol}=12.5mol$

To calculate the mole fraction of a substance, we use the equation:

$\chi_A=\frac{n_A}{n_A+n_B}$

Moles of KCl = 0.58 moles

Moles of water = 12.5 moles

Putting values in above equation:

$\chi_{KCl}=\frac{n_{KCl}}{n_{KCl}+n_{\text{water}}}$

$\chi_{KCl}=\frac{0.58}{0.58+12.5}\\\\\chi_{KCl}=0.044$

Hence, the mole fraction of KCl in the solution is 0.044

6 0

4 years ago

How is matter classified?

pshichka [43]

Matter is classified into two groups: Pure Substances and Mixtures.

5 0

3 years ago