Answer:
A: NaOH + HCl = NaCl +H2O
B: Volume of NaOH = 22.2ml
C: 
D: Volume of HCl = 9.45 ml
E: 
Explanation:
Part A: Balanced chemical equaion
NaOH + HCl = NaCl +H2O
part B:
Volume of NaOH used in titration is 22.2 ml because volume is taken upto the end point of the titration.
Part C:
Calculation of moles of NaOH used:
Part D:
Volume of HCl used in titration is 9.45 ml because volume is taken upto the end point of the titration.
Part E:
But in case of acid it is known as basicity and in case of base it is known as acidity.
in case of NaOH and HCl n-factor is 1;
hence
Normality=molarity;
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➷ Iron would be attracted to a magnet therefore, you can hover a magnet over the mixture. Doing this would lift out the iron fillings, leaving the sand behind.
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Density= mass/volume
step one :
convert m3 to ml
1m^3 =1000000ml
0.250m^3 x1000000=250000ml
step two: convert mg to g
1mg=0.001g, therefore 4.25 x108mg=0.459g
density is therefore= 0.459g/250000=1.836 x10^-6g/ml
Analytical chemistry -- A task that would fall into this area of chemistry is measuring the level of lead in drinking water.
<u>Answer:</u>
<em>The final volume must be 400 mL.</em>
<em></em>
<u>Explanation:</u>
Let us assume the Initial volume as 100ml
Using dilution factor formula
So,
Thus, the final volume must be 400 mL.
