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finlep [7]
3 years ago
9

7. Complete the following table, comparing forces within atoms.

Physics
1 answer:
umka21 [38]3 years ago
5 0

<u>Electromagnetic powers versus Molecules:  </u>

Electrons are kept in the circle around the core by the electromagnetic power, in light of the fact that the core in the focal point of the particle is decidedly charged and pulls in the contrarily charged electrons.  

<u> </u>

<u>Solid Nuclear power versus Molecules:  </u>

The solid atomic power holds most standard issue together on the grounds that it limits quarks into hadron particles, for example, the proton and neutron.  

<u>Feeble power versus Molecules:  </u>

In atomic material science and molecule physical science, the frail cooperation, which is additionally frequently called the powerless power or feeble atomic power, is the instrument of communication between subatomic particles that is liable for the radioactive rot of iotas.  

<u> </u>

<u>Gravity Vs. Particles:  </u>

Gravity influences molecules a similar way it influences all other issue. Each iota makes its own gravitational field which draws in all other issue known to man.

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What’s the difference between 40hz and 300hz
jarptica [38.1K]

Answer:

40hz has less frequency of sound and 300hz has more frequency of sound which means 40hz has less crest and troughs , so it has less reachability thank 300hz.

Explanation:

3 0
3 years ago
Trucks 1 and 2 are traveling at the same constant velocity but truck 1's energy due to motion is two times less than that of tru
brilliants [131]
Kinetic energy = 0.5 * m * v²

m mass
v velocity

If the velocity stays the same and the kinetic energy goes down by a factor of 2, the mass must go down by a factor of 2 also.
7 0
4 years ago
Two protons are released from rest when they are 0.750 {\rm nm} apart.
Alex787 [66]

Explanation:

Given:

m = 1.673 × 10^-27 kg

Q = q = 1.602 × 10^-19 C

r = 0.75 nm

= 0.75 × 10^-9 m

A.

Energy, U = (kQq)/r

Ut = 1/2 mv^2 + 1/2 mv^2

1.673 × 10^-27 × v^2 = (8.99 × 10^9 × (1.602 × 10^-19)^2)/0.75 × 10^-9

v = 1.356 × 10^4 m/s

B.

F = (kQq)/r^2

F = m × a

1.673 × 10^-27 × a = ((8.99 × 10^9 × (1.602 × 10-19)^2)/(0.075 × 10^-9)^2

a = 2.45 × 10^17 m/s^2.

4 0
3 years ago
a lorry travels 3600m on a test track accelerating constantly at 3m/s squared from standstill. what is the final velocity (3 sig
suter [353]

The final velocity of the truck is found as 146.969 m/s.

Explanation:

As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.

Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.

2as =v^{2} - u^{2} \\\\v^{2} = 2as + u^{2}

Then, the final velocity will be

v^{2} = 2 * 3 * 3600 + 0 = 21600\\ \\v=\sqrt{21600}=146.969 m/s

Thus,  the final velocity of the truck is found as 146.969 m/s.

8 0
3 years ago
Pls help me idk what to do
Alika [10]
The dot would be the earthquake epicenter. That is where the earthquake originated.
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