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3 years ago

13

An elephant with a mass of 600 kg is thrown out of an airplane and falls through the sky under the influence of gravity. What is

its weight as it falls toward the earth?

1 answer:

zloy xaker [14]3 years ago

8 0

Fg = m g

Fg = 600 × 9.8

Fg =5880 N

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1L of a solution of oxalic acid [(). ] contains 2.52g of acid.

alexandr1967 [171]

Answer:

0.028 M.

Explanation:

NOTE: This question is a chemistry question. However, the answer to the question can be obtained as shown below:

We'll begin by calculating the number of mole in 2.52 g of oxalic acid, C₂H₂O₄. This can be obtained as follow:

Mass of C₂H₂O₄ = 2.52 g

Molar mass of C₂H₂O₄ = (2×12) + (2×1) + (4×16)

= 24 + 2 + 64

= 90 g/mol

Mole of C₂H₂O₄ =?

Mole = mass / molar mass

Mole of C₂H₂O₄ = 2.52 / 90

Mole of C₂H₂O₄ = 0.028 mole

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Mole of C₂H₂O₄ = 0.028 mole

Volume = 1 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.028 / 1

Molarity = 0.028 M

Therefore, the molarity of the solution is 0.028 M.

5 0

3 years ago

A car moving at 10 m/s crashes into a large bush and stops in 1.3 m. Using the Work-Energy theorem, calculate the average force

ad-work [718]

Answer:

The magnitude of the average force the seat belt exerts on the passenger is 2692.3 N.

It takes 0.26 s to bring the passenger in the car to a halt.

Explanation:

Hi there!

The negative work (W) needed to bring a moving object to stop is equal to its kinetic energy (KE):

W = KE

F · s = 1/2 · m · v²

Where:

F = applied force on the passenger.

s = displacement of the passenger.

m = mass of the passenger.

v = velocity of the passenger.

Solving the equation for F:

F = 1/2 · m · v² / s

Replacing with the data:

F = 1/2 · 70 kg · (10 m/s)² / 1.3 m

F = 2692.3 N

The magnitude of the average force the seat belt exerts on the passenger is 2692.3 N.

According to the second law of Newton:

F = m · a

Where "a" is the acceleration of the passenger.

We also know from kinematics that the velocity of an object can ve calculated as follows:

v = v0 + a · t

Where:

v = velocity of the passenger at time t.

v0 = initial velocity.

t = time.

a = acceleration.

When the passenger stops, its velocity is zero. So replacing a = F/m, let´s solve the equation for the time it takes the passenger to stop:

v = v0 + a · t

0 = 10 m/s + (-2692.3 N/ 70 kg) · t

-10 m/s / (-2692.3 N/ 70 kg) = t

t =0.26 s

It takes 0.26 s to bring the passenger in the car to a halt.

5 0

3 years ago

A ball on a string makes 25.0 revolutions in 9.37 s, in a circle radius 0.450 m. What is it’s velocity?

Sauron [17]

The velocity of the ball is 12.5 m/s

Explanation:

The velocity of the ball is given by the ratio between the distance covered by the ball and the time taken:

$v=\frac{d}{t}$

First, we calculate the distance covered. We know that the radius of the circle is

r = 0.450 m

And the length of the circumference is

$L=2\pi r = 2\pi(0.750)=4.7 m$

The ball makes 25.0 revolutions, so a total distance of

$d=(25.0)L=(25.0)(4.7)=117.5 m$

In a time of

t = 9.37 s

So, its velocity is

$v=\frac{117.5}{9.37}=12.5 m/s$

Learn more about velocity here:

brainly.com/question/5248528

#LearnwithBrainly

3 0

3 years ago

Read 2 more answers

Why do we use other bonding theories in addition to the lewis model?

Setler [38]

Full Question:

Why do we use other bonding theories in addition to the lewis model?

a) Lewis model is not suitable for all molecules or ions. b) Lewis model cannot predict all of the properties of a molecule or ion. c) Lewis model is too complicated.

Answer:

b) Lewis model cannot predict all of the properties of a molecule or ion.

Explanation:

Lewis structures, also called electron-dot structures or electron-dot diagrams, are diagrams that show the bonding between atoms of a molecule, and the lone pairs of electrons that may exist in the molecule.

Lweis model does not explain the geometry of molecules, how the bonds form, or how the electrons are shared between the atoms hence the need to use other bonding theories.

8 0

4 years ago

AEROSPACE On the Moon, a falling object falls just 2.65 feet in the first second after being dropped. Each second it falls 5.3 f

aniked [119]

Answer:

d = 265 ft

Therefore, an object fall 265 ft in the first ten seconds after being dropped

Explanation:

This scenario can be represented by an arithmetic progression AP.

nth term = a + nd

Where a is the first term given as 2.63 ft.

d is the common difference and is given as 5.3ft.

n is the particular second/time.

To calculate how far the object would fall in the first 10 seconds, we can derive it using the sum of an AP.

d = nth sum = (n/2)(2a+(n-1)d)

Where n = 10 seconds

a = 2.65 ft

d = 5.3 ft

Substituting the values we have;

d = (10/2)(2×2.65 + (10-1)5.3)

d = 265 ft

Therefore, an object fall 265 ft in the first ten seconds after being dropped

4 0

3 years ago

Read 2 more answers