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julsineya [31]
3 years ago
11

How many grams of NaCL are required to prepare 50ml of a 2.0 molar solution​

Chemistry
1 answer:
Ksivusya [100]3 years ago
4 0

Answer:

5.85 gm.

Explanation:

We know that,

Normality =<u> Molarity × Molecular </u><u>weight</u>

Equivalent weight

Since molecular weight of NaCl= equivalent weight = 23+35.5 =58.5

Normality of NaCl= molarity=2

Now,

Normality= <u>weight</u><u> </u><u>in</u><u> </u><u>gram</u><u> </u><u>×</u><u>1000</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

Volume ×equivalent weight

Weight in gram is given by,

<u>=</u><u>Normality × Volume × equivalent </u><u>weight</u>

1000

= <u>2× 50 × 58.</u><u>5</u>

1000

=5.85 gm.

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Calculate the concentration of CO2 in water at 25 degrees Celsius when the pressure of CO2 over the solution is 4.5 atm. At 25 d
OLEGan [10]

Answer : The concentration of CO_2 is, 0.12 M

Explanation :

Using Henry's law :

C_{CO_2}=k_H\times p_{CO_2}

where,

C_{CO_2} = concentration of CO_2 = ?

p_{CO_2} = partial pressure of CO_2 = 4.5 atm

k_H = Henry's law constant  = 3.1\times 10^{-2}mol/L.atm

Now put all the given values in the above formula, we get:

C_{CO_2}=3.1\times 10^{-2}mol/L.atm\times (4.5atm)

C_{CO_2}=0.1395M\approx 0.12M

Thus, the concentration of CO_2 is, 0.12 M

5 0
3 years ago
State the definition of the partial molar Gibbs energy.
balu736 [363]

Explanation :

As we know that the Gibbs free energy is not only function of temperature and pressure but also amount of each substance in the system.

G=G(T,P,n_1,n_2)

where,

n_1\text{ and }n_2 is the amount of component 1 and 2 in the system.

Partial molar Gibbs free energy : The partial derivative of Gibbs free energy with respect to amount of component (i) of a mixture when other variable (T,P,n_j) are kept constant are known as partial molar Gibbs free energy of i^{th} component.

For a substance in a mixture, the chemical potential (\mu) is defined as the partial molar Gibbs free energy.

The expression will be:

\bar{G_i}=\mu_i=\frac{\partial G}{\partial n_i}_{(T,P,n_j)}

where,

T = temperature

P = pressure

n_i\text{ and }n_j is the amount of component 'i' and 'j' in the system.

4 0
3 years ago
Use the balanced equation to solve the problem.
harkovskaia [24]

Answer:

4.20 moles NF₃

Explanation:

To convert between moles of N₂ and NF₃, you need to use the mole-to-mole ratio from the balanced equation. This ratio consists of the coefficients of both molecules from the balanced equation. The molecule you are converting from (N₂) should be in the denominator of the ratio because this allows for the cancellation of units. The final answer should have 3 sig figs because the given value (2.10 moles) has 3 sig figs.

1 N₂ + 3 F₂ ---> 2 NF₃

2.10 moles N₂        2 moles NF₃
---------------------  x  ---------------------  =  4.20 moles NF₃
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7 0
2 years ago
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lozanna [386]

Answer : The atoms in this compound are Copper(Cu), Chlorine(Cl), Hydrogen(H), Oxygen(O).

Explanation :

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The formula of copper chloride bi-hydrate is CuCl_2.2H_2O.

Therefore, there are 4 atoms in this compound and they are Copper(Cu), Chlorine(Cl), Hydrogen(H) and Oxygen(O).

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I believe it is d. physical shape n particle amount (amount of particle increase if u gain weight right?), weight directly proportional to mass..
3 0
3 years ago
Read 2 more answers
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