Answer:
ΔS=2*m*Cp*ln((T1+T2)/(2*(T1*T2)^1/2))
Explanation:
The concepts and formulas that I will use to solve this exercise are the integration and the change in the entropy of the universe. To calculate the final temperature of the water the expression for the equilibrium temperature will be used. Similarly, to find the change in entropy from cold to hot water, the equation of the change of entropy will be used. In the attached image is detailed the step by step of the resolution.
It must be positive also
Explanation The energy is coming out of A back into b and then going into A again and out
The angular speed of the playground ride is determined as 0.3 rad/s.
<h3>
What is angular speed?</h3>
Angular speed is the rate at which an object changes it angles which we measure in radians in a given time.
<h3>
Angular speed of the ride</h3>
The angular speed of the ride if the ride makes one complete revolution is calculated as follows;
ω = θ/t
ω = 2π/t
where;
- ω is angular speed of the ride
- t is time of motion of the ride
one complete revolution = 2π radians
ω = 2π/21
ω = 0.3 rad/s
Thus, the angular speed of the playground ride is determined as 0.3 rad/s.
Learn more about angular speed here: brainly.com/question/24158647
#SPJ1
The complete question is below;
A playground ride requires 21 seconds to make one complete revolution, what is angular speed of the ride in radian per second.
Answer:
12 kg
Explanation:
Momentum before collision = momentum after collision
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂
After the collision, they have the same velocity, so v₁ = v₂ = v:
m₁ u₁ + m₂ u₂ = m₁ v + m₂ v
m₁ u₁ + m₂ u₂ = (m₁ + m₂) v
We know that m₁ = 6 kg, u₂ = 0 m/s, and v = u₁ / 3.
(6 kg) u₁ + m₂ (0 m/s) = (6 kg + m₂) (u₁ / 3)
(6 kg) u₁ = (6 kg + m₂) (u₁ / 3)
6 kg = (6 kg + m₂) (1/3)
18 kg = 6 kg + m₂
m₂ = 12 kg
