The balanced reaction would be as follows:
<span>3NaOH + H3PO4 --> Na3PO4 + 3H20
We are given the concentration and the amount of the reactants to be used. We use these values for the calculations as follows:
</span><span>How many mL of .225 M NaOH will react with 4.568g H3PO4?
4.568 g (1 mol / 98 g) ( 3 mol NaOH / 1 mol H3PO4 ) ( 1 L / .225 mol NaOH ) = 0.621 L or 621 mL of .225 NaOH</span>
Answer:
84.0 ppm is the concentration of Red 40 dy in the original sports drink.
Explanation:
Concentration of red dye in sport drink before dilution 
Volume of the sport drink before dilution 
Concentration of red dye in sport drink after dilution 
Volume of the sport drink after dilution 
( dilution )
84.0 ppm is the concentration of Red 40 dy in the original sports drink.
Assuming you are talking about the individual in space, Size and Weight changes in space due to the difference in gravity. Astronauts grow taller in space due to the micro-gravity they experience out of the earth's atmosphere.
It would not be:
Mass : Because mass is a measurement not dependent on gravity
Density : Astronauts do not blow out in bubbles once they leave the earth's atmosphere, therefore, we can deduct that density stays the same
Answer: 71.43g
Explanation: The RMM of NaHCO3 is
23+1+12+16(3)=84.
There is one carbon in NaHCO3 thus there are 1×12g of C in NaHCO3.
Thus
85gNaHCO3-----12g C
500gNaHCO3---- xgram
(500×12)÷84= 71.43
Answer:
The temperature of the water in both beakers will decrease
Explanation:
