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wlad13 [49]
3 years ago
14

Hey people text me at azieyafreeman2 at g mail dot com

Physics
2 answers:
butalik [34]3 years ago
8 0

Answer:

ok

Explanation:

or zo0m meet??

Triss [41]3 years ago
5 0

Answer:

alr bet

Explanation:

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mrs. knight drops her briefcase. when the briefcase lands on the floor, what is the reaction force to the action force of the br
Shalnov [3]

Answer:

The force of the floor on the briefcase

Explanation:

The briefcase hits the floor and stops the falling which is reacting to the briefcase that was falling and hits the floor.

The falling briefcase would be the action force because it is moving downward

and

The reaction force would be the floor because it will react on the briefcase.

Hope this Helps

8 0
2 years ago
Join my Kahoo t<br> pin-04454287<br><br> join if u like anime
PSYCHO15rus [73]

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8 0
2 years ago
Read 2 more answers
PLEASE HELP!!! WILL GET BRAINIEST
zysi [14]
Hello There


Answers: 

1) BEVs and hydrogen fuel cell vehicles are more promising for the future because they reduce gas emissions as well as CO2 which makes our planet less-pulluted

2) This is an opinion. Mine is that they should be required to at least have it be an option to buy.

I hope this helps
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4 0
3 years ago
The spring of modulus k = 200 n /m is compressed a distance of 300 mm and suddenly released with the system at rest. determine t
DiKsa [7]
I attached the missing picture.
Let's analyze the situation as spring goes from stretched to unstretched state.
When you stretch the string you have to use force against ( you are doing work) this energy is then stored in the spring in the form of potential energy. When we release the spring the energy is being used to push the two carts. When the spring reaches its unstretched length its whole initial potential energy has been used on the carts, and this is the moment when two carts have maximum velocity.
The potential energy of compressed ( stretched) spring is:
E_p=\frac{1}{2}kx^2
The kinetic energy of two carts is:
E_{k1}+E_{k2}=m_1\frac{v_1^2}{2}+m_2\frac{v_2^2}{2}
So we have:
E_p=E_{k1}+E_{k2}\\ \frac{1}{2}kx^2=m_1\frac{v_1^2}{2}+m_2\frac{v_2^2}{2}
Momentum also has to be conserved:
m_1v_1-m_2v_2=0\\ m_1v_1=m_2v_2\\ v_1=\frac{m_2}{m_1}v_2
Momentum before the release of the spring is zero so it has to stay zero. We plug this back into the expresion we got from law of conservation of energy and we get:
v_2^2=\frac{m_1^2}{m_2^2-m_1^2}kx^2=4.05\\&#10;v_2=\sqrt{4.05}=2.012\frac{m}{s}
Now we go back to the momentum equation:
v_1=\frac{m_2}{m_1}v_2\\&#10;v_1=4.69\frac{m}{s}

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3 years ago
What surrounds a magnet?
LiRa [457]
A magnetic field. the answer is d
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