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3 years ago

What is the percent compostion of anhydrous salt in the hydrate MgBr2 x 6H2O

Chemistry

1 answer:

docker41 [41]3 years ago

5 0

Answer:

Explanation:

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Which element has a smaller ionic radius than magnesium (Mg)?

barxatty [35]

Answer:

Na has atomic number 11

which is less than magnesium has atomic number 12

ANSWER IS D

Explanation:

aluminum or Al is atomic 13 and Ca or calcium is atomic number 20 and rubidium or Rb is atomic number 37

6 0

3 years ago

If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro

In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.

Molality=

$\frac{Number of moles of solute}{Mass of solvent in kg}$

Number of moles of solute, n=

$\frac{Given mass of the substance}{Molar mass of the substance}$

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,

$n= \frac{0.2 }{123.06}$

Number of moles of nitrobenzene, n= 0.0016 mol

Mass of 10.9 g of naphthalene in kg=0.0109

$Molality= \frac{0.0016}{0.0109 }$

Molality= 0.146 m

7 0

3 years ago

The half-reaction occurring at the cathode in the balanced reaction shown below is __________?2Ag(s) + 1/2 O2(g) + 2H+(aq) → 2Ag

Shtirlitz [24]

Answer:

Correct choice are C and D (they are both, the same).

Explanation:

Cathode is the positive(+) electrode where a reduction occurs.

Reduction is the chemical reaction where the oxidation state is reduced.

2Ag(s) + 1/2 O2(g) + 2H+(aq) → 2Ag+(aq) + H2O (l)

A. 2H2O (l) → O2 (g) + 4H+ (aq) + 4e-

B. 2Ag (s) → 2Ag+ (aq) + 2e-

C. 1/2 O2 (g) + 2H+ (aq) + 2e- → H2O (l)

D. 1/2 O2 (g) + 2H+ (aq) + 2e- → H2O (l)

C or D, are ok. They are the same equation.

Oxygen from ground state reduce the oxidation state from 0 to -2

3 0

3 years ago

How many kilocalories are required to increase the temperature of 15.6 g of iron from 122 °c to 355 °c. the specific heat of iro

Dmitriy789 [7]

Heat require to boil 15.6 g iron from 122 C0to 355 C0 whereas,

$Q = m s dT$

Where, m is mass of iron

s is specific heat of iron

d T is change in temperature in celcius

$= 15.6 g * 0.45 J /g /C * (355 - 122) = 1.63 * 10^3 J$

1 cal = 4.2 J

Then,

$Q = (1.63 * 10^3) /4.2 = 0.389 K cal$

Thus 0.389 k cal of enrgy is required by a 15.6 g Fe to reach to 355 C^0

4 0

3 years ago

Which of the following changes requires an oxidizing agent?

KatRina [158]

2F⁻ → F₂ + 2e⁻

(mainly electrochemical oxidation)

8 0

3 years ago

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