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3 years ago

How to electrons move from one orbital to another in atoms?

Chemistry

1 answer:

tatyana61 [14]3 years ago

7 0

Answer:

Electrons in each orbital contain a set quantity of energy.

Explanation:

As long as an electron remains in the same orbital, the energy content of that electron remains constant. Electrons can move between orbits by releasing or absorbing energy.

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PLEASE HELP!!!!!!!!!!!!!

monitta

Answer:

• The closing of the frontier

Explanation:

•• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier

8 0

3 years ago

A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?

Natalija [7]

Answer:

The new volume of the gas is 276.45 mL.

Explanation:

Charles's law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Charles's law is a law that mathematically says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

$\frac{V}{T} =k$

Analyzing an initial state 1 and a final state 2, it is satisfied:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case:

V1= 250 mL
T1= 293 K
V2= ?
T2= 324 K

Replacing:

$\frac{250 mL}{293 K} =\frac{V2}{324 K}$

Solving:

$V2=324 K*\frac{250 mL}{293 K}$

V2= 276.45 mL

The new volume of the gas is 276.45 mL.

4 0

3 years ago

What volume, in mL, of carbon dioxide gas is produced at STP by the decomposition of 0.242 g calcium carbonate (the products are

damaskus [11]

Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

Therefore, 2.42×10¯³ mole of CO2 will occupy = 2.42×10¯³ x 22400 = 54.21 mL

Therefore, 54.21 mL of CO2 were obtained from the reaction.

7 0

3 years ago

A. B. C. D. what could be the correct answer? Help me please

AlladinOne [14]

Answer:

Explanation:

5 0

3 years ago

Read 2 more answers

For a half-reaction in an acidic solution, which substances should you add to balance the equation?

solmaris [256]

Hello!

I believe the correct answer to this question is H+ and H2O.

I hope you found this helpful! :)

8 0

4 years ago