Answer:
i) Jn = q Dn
ii) Diffusion current and drift current will be doubled
Explanation:
<u>i) Determine the directions of the electron drift and diffusion current flow </u>
the electron concentration is higher on the right side of the N-type semiconductor hence any change in the concentration of electrons will cause <em>diffusion of electrons from right to left and electron drift is from left to right </em>and this is because the electrons in the semiconductor bar are attracted to the electric field.
Jn = q Dn ( electron diffusion current )
<u>ii) Determine what happens to the diffusion current and drift current If we double the electron concentration everywhere </u>
The electron diffusion current ( J'n ) = 2q Dn = 2Jn ( i.e. diffusion current doubles )
Drift current = ( Jdrift = nq*μn*ε)
when the electron concentration is double
Drift current = 2 ( nq*μn*ε )
hence the drift current will double