A shearing of 50N is applied to an aluminum rod with a length of 10m a cross sectional area of 1.0×10-5 and a shear modulus of 2
1 answer:
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The time required by the particles are as follows:
a. t = 1.5 seconds
b. t = 3 seconds
c. t = 0.4 seconds
<h3>What is the time required?</h3>The time required for the particles to be at several distances apart is calculated using the equation of motion given below:
a) Time required to be 30 m apart:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51 - 30
S1 + S2 = 21
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 21
2t^2 + 11t - 21 = 0
Solving for time, t by factorization, t = 1.5 seconds
b) Time required to meet:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 51
2t^2 + 11t - 51 = 0
Solving for time, t by factorization, t = 3 seconds
c) Time required for velocity of P is ¾ of the velocity of Q:
Using the equation of motion: V = u + at
Vp = 3/4 Vq
4Vp= 3Vq
Substituting the values:
4(5 + t) = 3(6 + 3t)
5t = 2
t = 0.4 seconds
Learn more about distance, velocity and acceleration at: brainly.com/question/14344386
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The correct answer is <span>B. As speed of a fluid increases, the pressure within decreases.
Using formulas, Bernoulli's principle can be written as
</span>
where p is the pressure of the fluid,
its density, v its speed, and h its elevation above a reference level.
Assuming h does not change, we can see that if the speed v increases, the pressure p must decrease in order to keep constant the sum of the three terms.
Using formulas, Bernoulli's principle can be written as
</span>
where p is the pressure of the fluid,
Assuming h does not change, we can see that if the speed v increases, the pressure p must decrease in order to keep constant the sum of the three terms.