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3 years ago

If 4 moles of O2 and 8 moles of N2 occupy a 12 L

Chemistry

1 answer:

IRISSAK [1]3 years ago

7 0

Answer:

P(N₂) = 4.02 atm

Explanation:

Number of moles of O₂ = 4 mol

Number of moles of N₂ = 8 mol

Total pressure = 6 atm

Partial pressure of N₂ = ?

Solution:

We will calculate the partial pressure by using mole friction.

P(N₂) = X(N₂)P(total)

X(N₂) = mol friction = moles of N₂ / total number of moles

X(N₂) = 8 mol / 12 mol = 0.67

Partial pressure of N₂:

P(N₂) = X(N₂)P(total)

P(N₂) = 0.67 × 6 atm

P(N₂) = 4.02 atm

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Morgarella [4.7K]

Answer:

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Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

$molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH} =6.03x10^{22}molec$

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

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$Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec$

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