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marta [7]
3 years ago
12

Why would it be cooler if you climb to a higher elevation in a desert

Physics
2 answers:
yulyashka [42]3 years ago
4 0

Not so sure, but the higher u go, the more colder it gets, for the warmer air stays down.
Arturiano [62]3 years ago
3 0
Because cool air rises and warm air falls, so if you wanted the cooler air, you would need to go to higher elevation 
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Figure 1.18 (Chapter 1) shows the Hoover Dam Bridge over
stiks02 [169]

Answer: 7.436 s

Explanation:

This situation is related to vertical motion, specifically free fall and can be modelled by the following equation:

y=y_{o}+V_{o} t+\frac{gt^{2}}{2}  

Where:

y= 0m is the final height of the object (when it makes splash)

y_{o}=271 m  is the initial height of the object

V_{o}=0 m/s  is the initial velocity of the object (it was dropped)

g=-9.8m/s^{2}  is the acceleration due gravity (directed downwards)

t is the time since the objecct is dropped until it makes splash

0=y_{o}+0+\frac{gt^{2}}{2}  

Clearing t:

t=\sqrt{\frac{-2y_{o}}{g}}  

t=\sqrt{\frac{-2(271 m)}{-9.8m/s^{2}}}  

Finally:

t=7.436 s  

6 0
3 years ago
How much voltage (in terms of the power source voltage bV) will the capacitor have when it has started at zero volts potential d
Archy [21]

Answer:

The voltage is   V =   0.993V_b

Explanation:

From the question we are told that

   The time that has passed is  t = \frac{\tau}{2}

 Here \tau is know as the time constant

    The voltage of the  power source is   V_b

Generally the voltage equation for charging a capacitor is mathematically represented as

       V =  V_b  [1 - e^{- \frac{t}{\tau} }]

=>   V =  V_b  [1 - e^{- \frac{\frac{\tau}{2}}{\tau} }]

=>   V =  V_b  [1 - e^{- \frac{\tau}{2\tau} }]

=>   V =  V_b  [1 - e^{- \frac{1}{2} }]

=>   V =   0.993V_b    

5 0
2 years ago
Why do we use microwaves to communicate berween earth and satellites
nlexa [21]
It’s frequency is high and microwaves can pass through the atmosphere of the Earth.
7 0
3 years ago
Read 2 more answers
Research the potential for a large earthquake off the coast of Oregon. What are two of the biggest concerns with a large earthqu
Sphinxa [80]

There is a 33% chance of a large earthquake off the coast of Oregon.

The two main concerns of a large earthquake are Gas fires and Tsunami .

Explanation:

Everytime a large earthquake hits in any other part of the world, We find a small earthquake hitting off the coast of Oregon.

So scientists feel that as United States is prone to Earthquakes, the people have to be prepared for such eventualities.

The main concern for this large earthquake is, that it might lead to gas leakages at homes that can start a gas fire, which might spread. So people have to be careful and check  on any gas leakages.

Such large earthquakes can also lead to tsunami waves. So people have to take precautions and evacuate, if they are near the coastline.

6 0
3 years ago
A man with a weight of 100 N is located
valentina_108 [34]

Answer:

Given,

  mass of man = 100 N = 10 kg

   height = h = 25m

   since the man does not move anything with his force, work done by him is zero

   work done on the man = gain in potential energy

   P.E=mgh

   P.E=10×9.8×25

  P.E=2.45KJ

Explanation:

so, potential energy gained by man is 2.45 KJ

5 0
2 years ago
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