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4 years ago

Why would it be cooler if you climb to a higher elevation in a desert

Physics

2 answers:

yulyashka [42]4 years ago

4 0

Not so sure, but the higher u go, the more colder it gets, for the warmer air stays down.

Arturiano [62]4 years ago

3 0

Because cool air rises and warm air falls, so if you wanted the cooler air, you would need to go to higher elevation

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An integrated circuit is a ___.

EastWind [94]

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Remember that an integrated circuit are the heart and brains of most circuits. They are the keystone of modern electronics.

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3 years ago

Which best explains why the receiver of a signal must understand the code or language being used

Oksi-84 [34.3K]

The receiver of a signal must understand the code or language being used to avoid confusion and losses.

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2 years ago

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3 years ago

Which is greater, the gravitational force between earth and the moon, or the force between earth and the sun?

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3 years ago

A straight segment of a current-carrying wire has a current element IL where I = 2.70 A and L = 3.20 cm i + 4.30 cm j. The segme

myrzilka [38]

The component of the force in negative z-direction is -0.144 N.

The given parameters;

<em>current in the wire, I = 2.7 A</em>
<em>length of the wire, L = (3.2 i + 4.3j) cm</em>
<em>magnetic filed, B = 1.24 i</em>

The force on the segment of the wire is calculated as follows;

$F = ILBsin(\theta)$

where;

<em>θ is the angle wire and magnetic field</em>

<em />

The force on the wire segment will be perpendicular in negative z-direction (applying right hand rule), so there won't be any x and y component of the force.

The angle between the wire and the magnetic field is calculated as follows;

$\theta = tan^{-1} (\frac{y}{x} )\\\\\theta = tan^{-1} (\frac{4.3}{3.2} )\\\\\theta = 53.3 \ ^0$

The magnitude of the wire length is calculated as follows;

$|l | = \sqrt{3.2^2 + 4.3^2} = 5.36 \ cm = 0.0536 \ m$

The component of the force in negative z-direction is calculated as;

$F_z = -ILB sin(\theta)\\\\F_z = -2.7 \times 0.0536 \times 1.24 \times sin(53.3)\\\\F_z = -0.144 \ N$

Thus, the component of the force in negative z-direction is -0.144 N.

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3 years ago