From the equation above the reacting ratio of KClO3 to O2 is 2:3 therefore the number of moles of oxygen produced is ( 4 x3)/2 = 6 moles since four moles of KClO3 was consumed
mass=relative formula mass x number of moles
That is 32g/mol x 6 moles =192grams
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+. If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
1. Energy as particles can't move without kinetic (movement) energy
2. I think it's Diffusion and Active Transport
Answer:
85.6 g
Explanation:
Step 1: Write the balanced combustion equation
C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O
Step 2: Calculate the moles corresponding to 140 g of H₂O
The molar mass of H₂O is 18.02 g/mol.
140 g × 1 mol/18.02 g = 7.77 mol
Step 3: Calculate the moles of C₃H₈ needed to produce 7.77 moles of H₂O
The molar ratio of C₃H₈ to H₂O is 1:4. The moles of C₃H₈ needed are 1/4 × 7.77 mol = 1.94 mol.
Step 4: Calculate the mass corresponding to 1.94 moles of C₃H₈
The molar mass of C₃H₈ is 44.10 g/mol.
1.94 mol × 44.10 g/mol = 85.6 g
.5336
using avogadro’s law
