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sdas [7]
3 years ago
14

A box weighing 43.2 N is pulled horizontally until it slides uniformly lat a constant

Physics
1 answer:
GREYUIT [131]3 years ago
5 0

Your diagram should include four forces:

• the box's weight, pointing down (magnitude <em>w</em> = 43.2 N)

• the normal force, pointing up (mag. <em>n</em>)

• the applied force, pointing the direction in which the box is sliding (mag. <em>p</em> = 6.30 N, with <em>p</em> for "pull")

• the frictional force, pointing oppoiste the applied force (mag. <em>f</em> )

The box is moving at a constant speed, so it is inequilibrium and the net forces in both the vertical and horizontal directions sum to 0. By Newton's second law, we have

<em>n</em> + (-<em>w</em>) = 0

and

<em>p</em> + (-<em>f</em> ) = 0

So then the forces have magnitudes

<em>w</em> = 43.2 N

<em>n</em> = <em>w</em> = 43.2 N

<em>p</em> = 6.30 N

<em>f</em> = <em>p</em> = 6.30 N

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Vfy=?

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If an atom has 13 protons and is currently electrically neutral, what must happen to give the same atom a positive charge of +2e
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anastassius [24]
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\rho is the resistivity
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R is the resistance
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the cross-sectional area is given by
A=\pi r^2
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5 0
3 years ago
Read 2 more answers
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