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katrin [286]
2 years ago
11

A student prepares two solutions as shown. The dots represent solute particles. The student wants to test the conductivity of ea

ch solution. Prior to carrying out the investigation, the student needs to identify the variables being controlled and the variables being changed between the two solutions.
A.
The volume of the solution and the number of solute particles are being changed between the two solutions, but the concentration of the solution is being held constant.

B.
The number of solute particles and the concentration of the solution are being changed between the two solutions, but the volume is being held constant.

C.
The number of solute particles is being changed between the two solutions, but the volume and concentration of the solution is being held constant.

D.
The volume of the solution and the concentration of the solution are being changed between the two solutions, but the number of solute particles is being held constant.
Chemistry
1 answer:
stealth61 [152]2 years ago
3 0

Answer:

I think its D

Explanation:

It cant be B or C bc the solute particles arent changing. And  its not A because the concentration isnt constant

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In which of the following phases of matter do molecules have the lowest amount of energy?
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Answer:

C. Solid

Explanation:

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Identify the group of elements that corresponds to each of the following generalized electron configurations and indicate the nu
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Answer:

(a) [Noble gas] ns² np⁵: Number of unpaired electron is 1 and belongs to group 17 i.e. halogen group of the periodic table.

(b) [noble gas] ns² (n-1)d²: Number of unpaired electron is 2 and belongs to group 4 of the periodic table.

(c) [noble gas] ns² (n-1)d¹⁰ np¹: Number of unpaired electron is 1 and belongs to group 13 of the periodic table.

(d)[noble gas] ns² (n-2)f⁶ : Number of unpaired electron is 6 and belongs to group 8 of the periodic table.

Explanation:

In the Periodic table, the chemical elements are arranged in 7 rows, called periods and 18 columns, called groups. They are organized in increasing order of atomic numbers.

(a) [Noble gas] ns² np⁵

As the total number of electrons in the p-orbital is 5. Therefore, the number of unpaired electron is 1.

This element has 2 electrons in ns orbital and 5 electrons in np orbital. <u>So there are 7 valence electrons.</u>

Therefore, this element belongs to the group 17 i.e. halogen group of the periodic table.

(b) [noble gas] ns² (n-1)d²

As the total number of electrons in the d-orbital is 2. Therefore, the number of unpaired electrons is 2.

This element has 2 electrons in ns orbital and 2 electrons in (n-1)d orbital. So there are <u>4 valence electrons.</u>

Therefore, this element belongs to the group 4 of the periodic table.

(c) [noble gas] ns² (n-1)d¹⁰ np¹

As the total number of electrons in the p-orbital is 1. Therefore, the number of unpaired electron is 1.

This element has 2 electrons in ns orbital and 1 electron in np orbital. So there are <u>3 valence electrons</u>.

Therefore, this element belongs to the group 13 of the periodic table.

(d)[noble gas] ns² (n-2)f⁶

As the total number of electrons in the f-orbital is 6. Therefore, the number of unpaired electron is 6.

This element has 2 electrons in ns orbital and 6 electrons in (n-2)f orbital. So there are <u>8 valence electrons.</u>

Therefore, this element belongs to the group 8 of the periodic table.

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The chemical formula for the anion present in the aqueous solution of Pb(C₂H₃O₂)₂ is C₂H₃O₂²⁻

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