Answer:
Please see the attached pictures.
Explanation:
☆ To ensure that each carbon has 4 bonds, fill the other bonds with Hs.
Answer:
Q >> Kc
We have more products than reactans. To reach the equilibrium, the balance will shift to the left.
Explanation:
Step 1: Data given
Temperature = 450.0 K
Kc = 4.62
When Kc > Q, we have more reactants than products. To reach the equilibrium, the balance will shift to the right
When Kc < Q, we have more products than reactans. To reach the equilibrium, the balance will shift to the left.
When Kc = Q,the equiation isatequilibrium
[SO3] = 0.254 M
[O2] = 0.00855 M
[SO2] = 0.500 M
Step 2: The balanced equation
2SO2(g) + O2(g) ⇄ 2SO3(g)
Step 3: Calculate the Q
Q = [SO3]² / [O2][SO2]²
Q = 0.254²/ (0.500 * 0.00855²)
Q = 1765
Q >> Kc
We have more products than reactans. To reach the equilibrium, the balance will shift to the left.
True
Carbon monoxide is a primary pollutant which no odor results from incomplete combustion of fuel. The man sources are gasoline and burning of biomass.
Depending on the source of emission, pollutants can be classified into two groups that is primary and secondary pollutants.
A primary pollutant is emitted in the atmosphere directly from a source. It can be either natural sch as volcanic eruptions, sandstorms or man-made that is due to industrial and vehicle emissions. Examples of primary pollutants are nitrogen oxides, carbon monoxide and particulate matter.
Secondary pollutant is due to interactions between primary and secondary pollutants. These can be chemical or physical interactions. Examples are photo-chemical oxidants and secondary particulate matter.
Therefore, carbon monoxide CO is a primary pollutant.
