What is the acceleration of the train
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Answer:
The kinetic energy lost by the electron ΔK.E is 3.5244 × 10⁻¹⁵ J
Explanation:
Here we have;
Change in electric potential, ΔV, of the screen = 25000 V
The energy gained by the electron can be derived from the relation of change in electrical potential energy, ΔEPE, as follows;
ΔEPE = -Charge, q × ΔV
Therefore, since charge, q = -1.602 × 10⁻¹⁹ C we have;
ΔEPE = -(-1.602 × 10⁻¹⁹ C) × 25,000 V = 3.5244 × 10⁻¹⁵ C·V =
Also, since the electron is accelerated to the screen by the electrical potential energy, we have;
From the principle of conservation of energy in a given system;
The change in potential energy, ΔEPE of the electrons = Change in kinetic energy, ΔK.E, of the electrons3.5244 × 10⁻¹⁵ J
Where:
m = Mass of the electron = 9.11 × 10⁻³¹ kg
= Initial velocity of the electrons = 0 m/s (electrons at rest)
= Final velocity of the electrons
Hence;
The kinetic energy lost by the electron ΔK.E = ΔEPE = 3.5244 × 10⁻¹⁵ J.